Python:究竟如何获取一个字符串,将其拆分、反转并再次将其连接在一起?

发布于 2024-09-17 09:41:07 字数 57 浏览 6 评论 0原文

到底如何使用 python 获取一个字符串、分割它、反转它并再次将它连接在一起,而无需括号、逗号等?

How exactly can you take a string, split it, reverse it and join it back together again without the brackets, commas, etc. using python?

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评论(5

浪菊怪哟 2024-09-24 09:41:32

我被要求在不使用任何内置函数的情况下这样做。所以我为这些任务编写了三个函数。这是代码 -

def string_to_list(string):
'''function takes actual string and put each word of string in a list'''
list_ = []
x = 0 #Here x tracks the starting of word while y look after the end of word.
for y in range(len(string)):
    if string[y]==" ":
        list_.append(string[x:y])
        x = y+1
    elif y==len(string)-1:
        list_.append(string[x:y+1])
return list_

def list_to_reverse(list_):
'''Function takes the list of words and reverses that list'''
reversed_list = []
for element in list_[::-1]:
    reversed_list.append(element)
return reversed_list

def list_to_string(list_):
'''This function takes the list and put all the elements of the list to a string with 
space as a separator'''
final_string = str()
for element in list_:
    final_string += str(element) + " "
return final_string

#Output
text = "I love India"
list_ = string_to_list(text)
reverse_list = list_to_reverse(list_)
final_string = list_to_string(reverse_list)
print("Input is - {}; Output is - {}".format(text, final_string))
#op= Input is - I love India; Output is - India love I 

请记住,这是一个更简单的解决方案。这是可以优化的,所以尝试一下。谢谢你!

I was asked to do so without using any inbuilt function. So I wrote three functions for these tasks. Here is the code-

def string_to_list(string):
'''function takes actual string and put each word of string in a list'''
list_ = []
x = 0 #Here x tracks the starting of word while y look after the end of word.
for y in range(len(string)):
    if string[y]==" ":
        list_.append(string[x:y])
        x = y+1
    elif y==len(string)-1:
        list_.append(string[x:y+1])
return list_

def list_to_reverse(list_):
'''Function takes the list of words and reverses that list'''
reversed_list = []
for element in list_[::-1]:
    reversed_list.append(element)
return reversed_list

def list_to_string(list_):
'''This function takes the list and put all the elements of the list to a string with 
space as a separator'''
final_string = str()
for element in list_:
    final_string += str(element) + " "
return final_string

#Output
text = "I love India"
list_ = string_to_list(text)
reverse_list = list_to_reverse(list_)
final_string = list_to_string(reverse_list)
print("Input is - {}; Output is - {}".format(text, final_string))
#op= Input is - I love India; Output is - India love I 

Please remember, This is one of a simpler solution. This can be optimized so try that. Thank you!

挖鼻大婶 2024-09-24 09:41:29

你是说这个吗?

from string import punctuation, digits

takeout = punctuation + digits

turnthis = "(fjskl) 234 = -345 089 abcdef"
turnthis = turnthis.translate(None, takeout)[::-1]
print turnthis

You mean this?

from string import punctuation, digits

takeout = punctuation + digits

turnthis = "(fjskl) 234 = -345 089 abcdef"
turnthis = turnthis.translate(None, takeout)[::-1]
print turnthis
余生共白头 2024-09-24 09:41:25

你的意思是这样吗?

import string
astr='a(b[c])d'

deleter=string.maketrans('()[]','    ')
print(astr.translate(deleter))
# a b c  d
print(astr.translate(deleter).split())
# ['a', 'b', 'c', 'd']
print(list(reversed(astr.translate(deleter).split())))
# ['d', 'c', 'b', 'a']
print(' '.join(reversed(astr.translate(deleter).split())))
# d c b a

Do you mean like this?

import string
astr='a(b[c])d'

deleter=string.maketrans('()[]','    ')
print(astr.translate(deleter))
# a b c  d
print(astr.translate(deleter).split())
# ['a', 'b', 'c', 'd']
print(list(reversed(astr.translate(deleter).split())))
# ['d', 'c', 'b', 'a']
print(' '.join(reversed(astr.translate(deleter).split())))
# d c b a
丑丑阿 2024-09-24 09:41:22

不适合 100% 这个特定的问题,但如果你想从后面分割,你可以这样做:

theStringInQuestion[::-1].split('/', 1)[1][::-1]

此代码从后面的符号“/”处分割一次。

Not fitting 100% to this particular question but if you want to split from the back you can do it like this:

theStringInQuestion[::-1].split('/', 1)[1][::-1]

This code splits once at symbol '/' from behind.

安静被遗忘 2024-09-24 09:41:19
>>> tmp = "a,b,cde"
>>> tmp2 = tmp.split(',')
>>> tmp2.reverse()
>>> "".join(tmp2)
'cdeba'

或更简单:

>>> tmp = "a,b,cde"
>>> ''.join(tmp.split(',')[::-1])
'cdeba'

这里的重要部分是 split 函数连接函数。要反转列表,您可以使用 reverse() (它会就地反转列表)或切片语法 [::-1] (它会返回一个新的反转列表)。

>>> tmp = "a,b,cde"
>>> tmp2 = tmp.split(',')
>>> tmp2.reverse()
>>> "".join(tmp2)
'cdeba'

or simpler:

>>> tmp = "a,b,cde"
>>> ''.join(tmp.split(',')[::-1])
'cdeba'

The important parts here are the split function and the join function. To reverse the list you can use reverse(), which reverses the list in place or the slicing syntax [::-1] which returns a new, reversed list.

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