使用 BuildEngine 传递 MsBuild 命令行参数

发布于 2024-09-17 06:53:50 字数 500 浏览 4 评论 0原文

我有以下代码可以从另一个 C# 应用程序构建项目：

var buildEngine = new Engine();

buildEngine.RegisterLogger(new ConsoleLogger());

var success = buildEngine.BuildProjectFile(pathToCsProjFile);
if(!success)
{
    Log.LogIt("On Noes! We Broke!");
}
else
{
    Log.LogIt("It Worked!!!!!!");
}

当前它构建默认配置（调试），但我希望它构建发布版本。如果我从命令行调用 MsBuild，我会执行以下操作：

C:\Windows\WinFX\v3.5>msbuild.exe *.proj /ToolsVersion:3.5 /p:Configuration=Release

如何将该配置开关传递给构建引擎？

原文

I have the following code to build a project from another C# app:

var buildEngine = new Engine();

buildEngine.RegisterLogger(new ConsoleLogger());

var success = buildEngine.BuildProjectFile(pathToCsProjFile);
if(!success)
{
    Log.LogIt("On Noes! We Broke!");
}
else
{
    Log.LogIt("It Worked!!!!!!");
}

Currently it builds the default configuration (Debug) but I want it to build the release version. If I were invoking MsBuild from the command line I would do something like:

C:\Windows\WinFX\v3.5>msbuild.exe *.proj /ToolsVersion:3.5 /p:Configuration=Release

How do I pass that configuration switch to the build engine?

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梦在深巷 2024-09-24 06:53:50

您需要设置该属性，类似这样的操作应该可以解决问题：

var pathToCsProjFile = "";
var buildEngine = new Engine();
var project = new Project(buildEngine);
project.Load(pathToCsProjFile);
project.SetProperty("Configuration", "Release");

var success = project.Build();

You'll want to set the property, something like this should do the trick:

var pathToCsProjFile = "";
var buildEngine = new Engine();
var project = new Project(buildEngine);
project.Load(pathToCsProjFile);
project.SetProperty("Configuration", "Release");

var success = project.Build();

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