PHP - 遍历目录并获取所有文件（图像）的代码

Question

我想编写一个页面，它将遍历指定的目录...并获取该目录中的所有文件...

在我的情况下，该目录将仅包含图像并显示图像及其链接...

类似这样

< img src="https://i.sstatic.net/ceiFy.png" alt="Example">

如何操作

ps 该目录不会是用户输入的..它将是同一目录总是...

Answer 1

您还可以尝试 glob 函数：

$path = '/your/path/';
$pattern = '*.{gif,jpg,jpeg,png}';

$images = glob($path . $pattern, GLOB_BRACE);

print_r($images);

Answer 2

我使用类似的东西：

if ($dir = dir('images'))
{       
    while(false !== ($file = $dir->read()))
    {
        if (!is_dir($file) && $file !== '.' && $file !== '..' && (substr($file, -3) === 'jpg' || substr($file, -3) === 'png' || substr($file, -3) === 'gif'))
        {
            // do stuff with the images
        }
    }
}
else { echo "Could not open directory"; }

Answer 3

您可以像其他人建议的那样检查目录中的每个文件，或者您可以使用 glob 根据扩展名识别文件。

Answer 4

/**
*  function get files 
*  @param $path string = path to fine files in 
*  @param $accept array = array of extensions to accept 
*  @param currentLevel = 0, stopLevel = 0 
*  @return array of madmanFile objects, but you can modify it to 
*  return whatever suits your needs.  
*/

    public static function getFiles( $path = '.', $accept, $currentLevel = 0, $stopLevel = 0){

            $path = trim($path);                    //trim whitespcae if any
            if(substr($path,-1)=='/'){$path = substr($path,0,-1);}  //cutoff the last "/" on path if provided
            $selectedFiles = array();
            try{
                    //ignore these files/folders
                    $ignoreRegexp = "/\.(T|t)rash/";
                    $ignore = array( 'cgi-bin', '.', '..', '.svn');
                    $dh = @opendir( $path );
                    //Loop through the directory
                    while( false !== ( $file = readdir( $dh ) ) ){
                            // Check that this file is not to be ignored
                            if( !in_array( $file, $ignore ) and !preg_match($ignoreRegexp,$file)){
                            $spaces = str_repeat( ' ', ( $currentLevel * 4 ) );
                                    // Its a directory, so we need to keep reading down...
                                    if( is_dir( "$path/$file" ) ){
                                            //merge current selectFiles array with recursion return which is
                                            //another array of selectedFiles
                                            $selectedFiles = array_merge($selectedFiles,MadmanFileManager::getFiles( "$path/$file", $accept, ($currentLe$
                                    } else{
                                            $info = pathinfo($file);
                                            if(in_array($info['extension'], $accept)){
                                                    $selectedFiles[] = new MadmanFile($info['filename'], $info['extension'], MadmanFileManager::getSize($

                                            }//end if in array
                                    }//end if/else is_dir
                            }
                    }//end while
                    closedir( $dh );
                    // Close the directory handle
            }catch (Exception $e){
                    echo 'Caught exception: ',  $e->getMessage(), "\n";
            }

            return $selectedFiles;
    }

Answer 5

您可以使用 DirectoryIterator

try {
    $dir = './';
    /* @var $Item DirectoryIterator */
    foreach (new DirectoryIterator($dir) as $Item) {
        if($Item->isFile()) {
            echo $Item->getFilename() . "\n";
        }
    }
} catch (Exception $e) {
    echo 'No files Found!<br />';
}

您好，如果您想递归地传递目录， ：
http://php.net/manual/en/class.recursivedirectoryiterator.php

Answer 6

您需要使用 scandir 函数来遍历列表目录中的文件。

Answer 7

<?php 
//define directory
$dir = "images/";
//open directory
if ($opendir = opendir($dir)){
//read directory
 while(($file = readdir($opendir))!= FALSE ){
  if($file!="." && $file!= ".."){
   echo "<img src='$dir/$file' width='80' height='90'><br />";
  }
 }
} 
?>

来源：phpacademy.org

Answer 8

if ($handle = opendir('.')) {
    while (false !== ($file = readdir($handle))) {
        if ($file != "." && $file != "..") {
            echo "$file\n";
        }
    }
    closedir($handle);
}

使用 readdir