QT4中没有这个信号

发布于 2024-09-16 23:37:16 字数 870 浏览 4 评论 0原文

我有一个信号和一个插槽,应该可以很好地配合在一起。

class MemberVisitor: public QObject
{
    Q_OBJECT
signals:
    void processMember(Member* member, bool &breakLoop);
public:
    void processList(QList<Member*>* list);
};

以及:

class MemberFinder: public QObject
{
    Q_OBJECT
public slots:
    void processMember(Member* member, bool &breakLoop);
public:
    Member* member();
    MemberFinder(QString memID): m_member(0), m_memID(memID) {};
private:
    Member* m_member;
    QString m_memID;
};

并不复杂,对吧?但我肯定错过了一些东西,因为 QT 不断给我错误:“Object::connect: OperationsOnMembers.cpp:29 中没有这样的信号 MemberVisitor::processMember()”

这是应该将它们连接起来的代码:

QObject::connect(visitor, SIGNAL(processMember()), finder, SLOT(processMember()));

我已经还尝试了所有合理的替代方案,例如在查找器上调用该函数。但我一直遇到同样的问题。我缺少什么?

I have a signal and a slot that should fit together quite nicely.

class MemberVisitor: public QObject
{
    Q_OBJECT
signals:
    void processMember(Member* member, bool &breakLoop);
public:
    void processList(QList<Member*>* list);
};

along with:

class MemberFinder: public QObject
{
    Q_OBJECT
public slots:
    void processMember(Member* member, bool &breakLoop);
public:
    Member* member();
    MemberFinder(QString memID): m_member(0), m_memID(memID) {};
private:
    Member* m_member;
    QString m_memID;
};

Not exactly complex, right? But I am definitely missing something, because QT keeps giving me the error: "Object::connect: No such signal MemberVisitor::processMember() in OperationsOnMembers.cpp:29"

Here's the code that should be hooking them up:

QObject::connect(visitor, SIGNAL(processMember()), finder, SLOT(processMember()));

I've also tried all the reasonable alternatives, like calling the function on finder. But I keep getting the same problem. What am I missing?

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评论(2

你的背包 2024-09-23 23:37:16

connect() 的调用应该是:

QObject::connect(visitor, SIGNAL(processMember(Member*, bool&)), 
    finder, SLOT(processMember(Member*, bool&)));

..假设访问者和查找者是指针。

The call to connect() should be:

QObject::connect(visitor, SIGNAL(processMember(Member*, bool&)), 
    finder, SLOT(processMember(Member*, bool&)));

..provided that visitor and finder are pointers.

半步萧音过轻尘 2024-09-23 23:37:16

您需要在 QObject::connect() 调用中包含参数类型(但不包含参数名称)。例如,

QObject::connect(visitor, SIGNAL(processMember(Member*, bool&)), finder, SLOT(processMember(Member*, bool&)));

这还允许您重载信号和槽,因此您可以发出具有相同名称但不同参数的信号(与函数重载相同,这基本上就是槽)。

这还允许您将信号连接到参数较少的插槽。如果您的会员查找器有第二个插槽:

class MemberFinder: public QObject
{
    Q_OBJECT
public slots:
    void processMember(Member* member, bool &breakLoop);
    void processMember(Member* member);
public:
    Member* member();
    MemberFinder(QString memID): m_member(0), m_memID(memID) {};
private:
    Member* m_member;
    QString m_memID;
};

您可以将相同的信号连接到第二个插槽,如下所示:

QObject::connect(visitor, SIGNAL(processMember(Member*, bool&)), finder, SLOT(processMember(Member*)));

You need to include the parameter types (but not the parameter names) in the QObject::connect() call. e.g.

QObject::connect(visitor, SIGNAL(processMember(Member*, bool&)), finder, SLOT(processMember(Member*, bool&)));

That also lets you overload signals and slots, so you can emit signals with the same name but different parameters (same as overloading of a function, which is basically what a slot is).

This also lets you connect a signal to a slot that has fewer parameters. If your Member finder had a second slot as such :

class MemberFinder: public QObject
{
    Q_OBJECT
public slots:
    void processMember(Member* member, bool &breakLoop);
    void processMember(Member* member);
public:
    Member* member();
    MemberFinder(QString memID): m_member(0), m_memID(memID) {};
private:
    Member* m_member;
    QString m_memID;
};

You could connect the same signal to the second slot as such :

QObject::connect(visitor, SIGNAL(processMember(Member*, bool&)), finder, SLOT(processMember(Member*)));
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