使用“this()”调用重载方法的正确语法是什么？在 C# 中？

发布于 2024-09-16 22:49:43 字数 239 浏览 9 评论 0原文

我可能有这个错误，但我已经看到了创建在定义中调用自身的重载方法的方法。它是这样的：

public void myFunction(int a, int b)
{
    //Some code here
}

public void myFunction(int a) : this (a, 10)
{ }

我知道这不是正确的语法，但由于某种原因我无法在任何地方找到正确的语法。正确的语法是什么？

原文

I may have this wrong, but I've seen the way of creating an overloaded method that calls itself in the definition. It's something like:

public void myFunction(int a, int b)
{
    //Some code here
}

public void myFunction(int a) : this (a, 10)
{ }

This is not the correct syntax, I know, but I can't find the correct syntax anywhere for some reason. What is the correct syntax for this?

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最舍不得你 2024-09-23 22:49:43

您将构造函数语法与方法语法混淆了。对于方法来说，执行此操作的唯一方法是显而易见的：

public void myFunction(int a, int b) 
{ 
    //Some code here 
} 

public void myFunction(int a) 
{ 
     myFunction(a, 10) ;
}

尽管从 C#4 开始，您可以使用可选参数：

public void myFunction(int a, int b = 10) 
{ 
    //Some code here 
}

您编写的内容对于构造函数来说几乎是正确的：

public class myClass
{

    public myClass(int a, int b)
    {
        //Some code here
    }

    public myClass(int a) : this (a, 10)
    { }

}

You are confusing constructor syntax for method syntax. The only way to do that for a method is the obvious:

public void myFunction(int a, int b) 
{ 
    //Some code here 
} 

public void myFunction(int a) 
{ 
     myFunction(a, 10) ;
}

although as of C#4, you can use a optional parameters:

public void myFunction(int a, int b = 10) 
{ 
    //Some code here 
}

What you wrote is close to right for constructors:

public class myClass
{

    public myClass(int a, int b)
    {
        //Some code here
    }

    public myClass(int a) : this (a, 10)
    { }

}

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花间憩 2024-09-23 22:49:43

只需这样做：

public void myFunction(int a, int b)
{
    //Some code here
}

public void myFunction(int a) 
{
    myFunction(a, 10)
}

您将重载与覆盖混淆了。您可以从派生类调用基构造函数，如下所示：

public MyConstructor(int foo) 
   :base (10)
{}

Just do this:

public void myFunction(int a, int b)
{
    //Some code here
}

public void myFunction(int a) 
{
    myFunction(a, 10)
}

You're confusing overloading with overriding. You can call a base constructor from an derived class like this:

public MyConstructor(int foo) 
   :base (10)
{}

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最笨的告白 2024-09-23 22:49:43

public class BaseClass {
     public virtual void SomeFunction(int a, int b) {}
}

public class Derived : BaseClass {
     public override SomeFunction(int a, int b) {
          base.SomeFunction(a, b * 10);
     }
}

public class BaseClass {
     public virtual void SomeFunction(int a, int b) {}
}

public class Derived : BaseClass {
     public override SomeFunction(int a, int b) {
          base.SomeFunction(a, b * 10);
     }
}

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