SQL 2005 - 表值函数编译正常，但在选择时会抛出错误语法近..

Question

该表值函数编译正常，

alter function [dbo].[ftsls031nnnHades](@withExpiredEntries smallint ) returns 
@t table( comno     varchar(3), 
        t$cuno      varchar(6),
        t$cpgs      varchar(6),
        t$dile      float,
        t$qanp      float,
        t$stdt      varchar(10),
        t$tdat      varchar(10),
        t$disc      float,
        t$damt      float,
        t$cdis      char(3),
        t$gnpr      float,
        t$refcntd   float,
        t$refcntu   float) as
------------------------------------------------------*/
/*-------------------------------------------------------
declare @withExpiredEntries bit; set @withExpiredEntries =0
declare @t table( comno     varchar(3), 
        t$cuno      varchar(6),
        t$cpgs      varchar(6),
        t$dile      float,
        t$qanp      float,
        t$stdt      varchar(10),
        t$tdat      varchar(10),
        t$disc      float,
        t$damt      float,
        t$cdis      char(3),
        t$gnpr      float,
        t$refcntd   float,
        t$refcntu   float)
------------------------------------------------------*/
Begin
set quoted_identifier off
if (@withExpiredEntries = 0) -- without expired entries
    Begin
        insert @t
        select * 
        from openQuery(Hades ,"select '010' comno, trim(t$cuno) t$cuno,trim(t$cpgs) t$cpgs,t$dile,t$qanp,to_char(t$stdt,'dd Mon yy') t$stdt,to_char(t$tdat,'dd Mon yy') t$tdat,to_char(t$disc,'999.99') t$disc,t$damt,t$cdis,t$gnpr,t$refcntd,t$refcntu from baan.ttdsls031010 where (to_char(t$Tdat,'yyyy-mm-dd') >= To_char(current_date,'yyyy-mm-dd')) and (to_char(t$stdt,'yyyy-mm-dd') <= To_char(current_date,'yyyy-mm-dd')) 
               union all       select '020' comno, trim(t$cuno) t$cuno,trim(t$cpgs) t$cpgs,t$dile,t$qanp,to_char(t$stdt,'dd Mon yy') t$stdt,to_char(t$tdat,'dd Mon yy') t$tdat,to_char(t$disc,'999.99') t$disc,t$damt,t$cdis,t$gnpr,t$refcntd,t$refcntu from baan.ttdsls031020 where (to_char(t$tdAt,'yyyy-mm-dd') >= To_char(current_date,'yyyy-mm-dd')) and (to_char(t$stdt,'yyyy-mm-dd') <= To_char(current_date,'yyyy-mm-dd'))")
    return  
End
    insert @t
    select * 
        from openQuery(Hades ,"select '010' comno, trim(t$cuno) t$cuno,trim(t$cpgs) t$cpgs,t$dile,t$qanp,to_char(t$stdt,'dd Mon yy') t$stdt,to_char(t$tdat,'dd Mon yy') t$tdat,to_char(t$disc,'999.99') t$disc,t$damt,t$cdis,t$gnpr,t$refcntd,t$refcntu from baan.ttdsls031010  
               union all       select '020' comno, trim(t$cuno) t$cuno,trim(t$cpgs) t$cpgs,t$dile,t$qanp,to_char(t$stdt,'dd Mon yy') t$stdt,to_char(t$tdat,'dd Mon yy') t$tdat,to_char(t$disc,'999.99') t$disc,t$damt,t$cdis,t$gnpr,t$refcntd,t$refcntu from baan.ttdsls031020   ")
    return
end

时，它会抛出此错误

当选择Msg 102, Level 15, State 1, Line 1 'select '010' comno、trim(t$cuno) t$cuno,trim(t$cpgs) t$cpgs,t$dile,t$qanp,to_char(t$stdt,'dd Mon yy') 附近语法不正确t$stdt,to_char(t$tdat,'dd'.

Answer 1

将双引号更改为单引号，看看会发生什么...

...
..Hades ,'select '010' comno...
...

您还必须将所包含的单引号加倍。

当 SET QUOTED_IDENTIFIER 为 ON 时，“ 分隔对象/列名称等。不是字符串。这也是默认设置。

SET QUOTED_IDENTIFIER OFF 在运行时没有任何意义：它是在 CREATE/ALTER 时间设置的...这就是为什么您在运行时而不是 CREATE 时间收到错误的原因。CREATE <>顺便编译一下...它在运行时编译为计划。