php glob() 不返回所有文件
我搜索了这个网站，发现了一段非常有用的代码片段，我已经能够使用了。
$counter = 0;
foreach (glob("images/gallery/photo_gallery/resized/*.jpg") as $pathToThumb)
{
$filename = basename($pathToThumb);
$pathToLarge = 'images/gallery/photo_gallery/' . $filename;
echo ('<a href="'.$pathToLarge.'"><img src="'.$pathToThumb.'" /></a>');
$counter++;
}
但由于某种原因，这只会返回我目录中的前 30 张图像。 （有 81 个）有人能想到为什么会发生这种情况吗？
谢谢。
I searched this site and found a very useful snippet of code that i've been able to use.
$counter = 0;
foreach (glob("images/gallery/photo_gallery/resized/*.jpg") as $pathToThumb)
{
$filename = basename($pathToThumb);
$pathToLarge = 'images/gallery/photo_gallery/' . $filename;
echo ('<a href="'.$pathToLarge.'"><img src="'.$pathToThumb.'" /></a>');
$counter++;
}
But for some reason this will only return the first 30 images in my directory. (there are 81) Can anyone think why this is happening?
Thanks.
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正如我上面所说
就足够了。或者，如果您顽固地只想要 jpg，
正如手册所建议的那样
As I have said above
would be enough. or, if you stubbornly wants only jpg only,
as manual suggests
感谢大家的意见。
答案是 - 在 glob() 中使用时，文件扩展名是区分大小写的（我不知道这一点）。
我的 30 个文件以 .jpg 结尾，而其余文件已通过大小调整程序自动重命名为 .JPG
所以这意味着
glob("imagesPath/*.jpg")仅返回小写匹配项。另一个教训:)
希望这个答案也可以帮助其他人。 :)
Thanks to everyone for input.
Here's the answer - file extensions are CASE-SENSITIVE when used in glob() (something I was un-aware of)
30 of my files end in .jpg whilst the remaining files have been auto renamed through a resizing program to .JPG
So this means
glob("imagesPath/*.jpg")only returned the lower-case matches.Another lesson learnt :)
Hopefully this answer can help someone else too. :)