“%sUser”是什么意思和“%d”这段代码的意思是？
PHP 函数：
public static function getById($uid)
{
$u = new User();
$query = sprintf('SELECT USERNAME, PASSWORD, EMAIL_ADDR, IS_ACTIVE ' .
'FROM %sUSER WHERE USER_ID = %d',
DB_TBL_PREFIX,
$uid);
$result = mysql_query($query, $GLOBALS['DB']);
if (mysql_num_rows($result))
{
$row = mysql_fetch_assoc($result);
$u->username = $row['USERNAME'];
$u->password = $row['PASSWORD'];
$u->emailAddr = $row['EMAIL_ADDR'];
$u->isActive = $row['IS_ACTIVE'];
$u->uid = $uid;
}
mysql_free_result($result);
return $u;
}
请帮助我，我无法理解这个“%sUser”和“%d”的含义
PHP function:
public static function getById($uid)
{
$u = new User();
$query = sprintf('SELECT USERNAME, PASSWORD, EMAIL_ADDR, IS_ACTIVE ' .
'FROM %sUSER WHERE USER_ID = %d',
DB_TBL_PREFIX,
$uid);
$result = mysql_query($query, $GLOBALS['DB']);
if (mysql_num_rows($result))
{
$row = mysql_fetch_assoc($result);
$u->username = $row['USERNAME'];
$u->password = $row['PASSWORD'];
$u->emailAddr = $row['EMAIL_ADDR'];
$u->isActive = $row['IS_ACTIVE'];
$u->uid = $uid;
}
mysql_free_result($result);
return $u;
}
Pls help me i can't understand what did mean by this "%sUser" and "%d"
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评论（2）
%s是一个“字符串”，将被替换为DB_TBL_PREFIX的值%d是一个数字，将被替换为值$uidhttps://www.php。 net/manual/en/function.sprintf.php
%sis a "String" and is being replaced by the value ofDB_TBL_PREFIX%dis a number, which is being replaced by the value of$uidhttps://www.php.net/manual/en/function.sprintf.php
%s和%d是sprintf的字符串参数的类型说明符。在此处查看该函数的文档：https://www.php.net/sprintf。%sand%dare type specifiers for the string argument tosprintf. Check out the docs for the function here: https://www.php.net/sprintf.