如何从顺序异或过程的最终结果输出中找到原始值？
问题是我想获取B的原始值，或者C或A的原始值。代码如下：
Dim strA As String = "A"
Dim strB As String = "B"
Dim strC As String = "C"
Dim result As Byte = 0
' Fetch the byte character code of strings and Xor them all into the result in a sequence.
result = result Xor AscW(strA)
result = result Xor AscW(strB)
result = result Xor AscW(strC)
' the final result value is 64
如何做到这一点？请帮助我找到解决此问题的正确方法。如果可以有另一个参数，当应用公式时可以显示原始值：“A”，“B”，“C”。谢谢。
The problem is that I want to get the original values of B, or the original value of C or A. Here is the code:
Dim strA As String = "A"
Dim strB As String = "B"
Dim strC As String = "C"
Dim result As Byte = 0
' Fetch the byte character code of strings and Xor them all into the result in a sequence.
result = result Xor AscW(strA)
result = result Xor AscW(strB)
result = result Xor AscW(strC)
' the final result value is 64
How to do this? Please help me with the correct solution to this problem. If there can be another parameter which when applied with a formula may reveal the original values: "A", "B", "C". Thank you.
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如果我正确理解你的问题，这是不可能的。有多种方法可以将
result拆分回strA、strB和strC。为了更容易理解原因，请考虑加法。假设您从 A = 5、B = 6 和 C = 7 开始。总和为 18。现在假设您从 A = 1、B = 1 和 C = 16 开始。总和仍然是 18。底线：如果您全部是“18”，无法将其拆分回来，因为多个输入给出相同的输出。
If I understand your question correctly, this is simply not possible. There are multiple ways to split
resultback intostrA,strBandstrC.To make it easier to see why, consider addition instead. Suppose you start with A = 5, B = 6 and C = 7. The sum is 18. Now suppose you start with A = 1, B = 1 and C = 16. The sum is still 18. Bottom line: if all you have is "18" there's no way to split it back, because multiple inputs give the same output.