gtkmm statusicon 创建后退出

发布于 2024-09-16 06:11:21 字数 1316 浏览 2 评论 0原文

我必须创建一个简单的应用程序，在系统托盘中显示一个图标和一个菜单，您可以从中执行一些操作。问题是 statusicon 在创建后立即关闭。缺少什么？我放置了睡眠以确保它已创建。系统托盘中会出现 3 秒钟的内容，即使它不是我设置的图标。

初始化.cc

#include <gtkmm/main.h>
#include "Tray.h"

int main(int argc, char *argv[]) {
    Gtk::Main kit(argc, argv);
    printf("Statuicon starting\n");
    Tray tray;
    printf("Statuicon started\n");
    return 0;
}

托盘.cc

#include "Tray.h"

Tray::Tray() {
    set(Gtk::Stock::OK);

    signal_activate().connect(sigc::mem_fun(*this, &Tray::on_statusicon_activated));
    signal_popup_menu().connect(sigc::mem_fun(*this, &Tray::on_statusicon_popup));

    set_visible(true);

    printf("Statusicon created\n");

    sleep(3);
}

Tray::~Tray() {}

void Tray::on_statusicon_popup(guint button, guint activate_time) {
    printf("popup!");
}

void Tray::on_statusicon_activated() {
    printf("active!");
}

托盘.h

#ifndef GTKMM_TRAY_H
#define GTKMM_TRAY_H
#include <gtkmm.h>
#include <unistd.h>
using namespace std;

class Tray : public Gtk::StatusIcon {
    public:
        Tray();
        ~Tray();

    private:
        virtual void on_statusicon_popup(guint button, guint activate_time);
        virtual void on_statusicon_activated();
};

#endif //GTKMM_TRAY_H

原文

I have to create a simple application that displays an icon in the systray and a menu from which you can do some operations.
the problem is that statusicon is closed immediately after creation. What's missing?
I put the sleep to make sure it was created. for 3 seconds something appears in systray, even if it is not the icon that I set.

Init.cc

#include <gtkmm/main.h>
#include "Tray.h"

int main(int argc, char *argv[]) {
    Gtk::Main kit(argc, argv);
    printf("Statuicon starting\n");
    Tray tray;
    printf("Statuicon started\n");
    return 0;
}

Tray.cc

#include "Tray.h"

Tray::Tray() {
    set(Gtk::Stock::OK);

    signal_activate().connect(sigc::mem_fun(*this, &Tray::on_statusicon_activated));
    signal_popup_menu().connect(sigc::mem_fun(*this, &Tray::on_statusicon_popup));

    set_visible(true);

    printf("Statusicon created\n");

    sleep(3);
}

Tray::~Tray() {}

void Tray::on_statusicon_popup(guint button, guint activate_time) {
    printf("popup!");
}

void Tray::on_statusicon_activated() {
    printf("active!");
}

Tray.h

#ifndef GTKMM_TRAY_H
#define GTKMM_TRAY_H
#include <gtkmm.h>
#include <unistd.h>
using namespace std;

class Tray : public Gtk::StatusIcon {
    public:
        Tray();
        ~Tray();

    private:
        virtual void on_statusicon_popup(guint button, guint activate_time);
        virtual void on_statusicon_activated();
};

#endif //GTKMM_TRAY_H

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陌上芳菲 2024-09-23 06:11:21

您根本没有运行主循环，因此无法处理任何输入事件，并且程序在构建托盘后退出。您想要做的是删除睡眠，然后在 main() 函数中，在 return 之前添加以下行：

Gtk::Main::run();

然后，当您希望应用程序退出时（通常是响应某种事件），请调用

Gtk::Main::quit();

You're not running a main loop at all, so no input events can be handled and the program exits after constructing the tray. What you want to do is delete the sleep, and then in your main() function, add the following line right before the return: