NSURLRequest 中的转义字符
我正在尝试在 iPhone 上使用 HTTP POST 将请求传递到 URL。 HTTP 正文包含一些转义字符。
NSString *requestMessage=[NSString stringWithString:@"?username/u001password/u001description"];
NSMutableURLRequest *url=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://welcome.com"]];
[url setHTTPMethod:@"POST"];
[url setHTTPBody:[requestMessage dataUsingEncoding:NSUTF8StringEncoding]];
NSURLConnection *theConnection=[[NSURLConnection alloc] initWithRequest:url delegate:self];
这里的转义字符是/u001。
使用此代码我没有得到任何正确的响应。我认为问题仅在于转义字符。请给我一个解决方案，如何在 Cocoa 中给出这样的转义序列。提前致谢。
I'm trying to pass a request to a URL using HTTP POST on iPhone. The HTTP body contains some escape characters.
NSString *requestMessage=[NSString stringWithString:@"?username/u001password/u001description"];
NSMutableURLRequest *url=[NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"http://welcome.com"]];
[url setHTTPMethod:@"POST"];
[url setHTTPBody:[requestMessage dataUsingEncoding:NSUTF8StringEncoding]];
NSURLConnection *theConnection=[[NSURLConnection alloc] initWithRequest:url delegate:self];
The escape character here is /u001.
Using this code I don't get any correct responses. I think the trouble is with the escape characters only. Please give me a solution for how to give an escape sequence like this in Cocoa. Thanks in advance.
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您混淆了正斜杠 (/) 和反斜杠 (\)。您需要一个反斜杠来形成转义序列；斜杠就是斜杠，“/u001”就是斜杠、字母 u、两个数字 0 和一个数字 1。
也就是说，如果您确实想在字符串中包含 U+0001，即使
\u001也是错误的。你想要\x01或者可能\u0001（但我似乎记得如果你使用\u来表示低于 U+ 的字符，GCC 会抱怨0100）。我确实想知道为什么服务器需要 U+0001 作为分隔符。是否有适用于您查询的任何服务器的公共 API 文档？
You've confused forward slashes (/) with backslashes (\). You need a backslash to form an escape sequence; a slash is just a slash, and “/u001” is just a slash, the letter u, two digits zero, and a digit one.
That said, if you actually want to include U+0001 in your string, even
\u001is wrong. You want\x01or maybe\u0001(but I seem to remember that GCC complains if you use\ufor a character lower than U+0100).I do wonder why the server would require U+0001 as the separator, though. Are there public API docs for whatever server you're querying?
你想逃避什么？我不太明白你想做什么。你想写“&”吗？然后就去做吧。它不是 HTML。
除此之外，
[NSString stringWithString:@"…constant string…"]是超流体的。@"...常量字符串..."就是您所需要的。NSString 中有一个方法可以向 URL 添加百分比转义符：
-(void)stringByAddingPercentEscapesUsingEncoding:。也许这就是您正在寻找的？What do you want to escape? I don't quite understand what you are trying to do. Do you want to write "&"? Then do it. It's not HTML.
Besides that,
[NSString stringWithString:@"…constant string…"]is superfluid.@"…constant string…"is all you need.There is a method in NSString to add percent-escapes to URLs:
-(void)stringByAddingPercentEscapesUsingEncoding:. Maybe that's what you're looking for?