重命名文件的 Shell 脚本

发布于 2024-09-16 04:25:35 字数 827 浏览 3 评论 0原文

我根据在这里找到的示例编写了一个小型 shell 脚本：https://bbs。 archlinux.org/viewtopic.php?id=36305

它采用这个：

bash-3.2$ ls
test 001  test 002  test 003  test 004

并将其变成：

bash-3.2$ ls
001  002  003  004  rename.sh

但是它给了我这个错误（即使它有效）：

bash-3.2$ ./rename.sh
mv: missing destination file operand after `rename.sh'
Try `mv --help' for more information.
`test 001' -> `001'
`test 002' -> `002'
`test 003' -> `003'
`test 004' -> `004'

虽然它工作正常，但很高兴看到我在哪里搞砸了，我认为默认情况下它会将文件放在同一目录中（这是所需的输出）。

#!/bin/bash
ls | while read -r FILE
do
        mv -v "$FILE" `echo $FILE | awk -F ' ' '{print $2}'`
done

预先感谢您帮助我纠正错误的代码。

原文

I wrote a small shell script based on an example I found here: https://bbs.archlinux.org/viewtopic.php?id=36305

it takes this:

bash-3.2$ ls
test 001  test 002  test 003  test 004

and turns it into:

bash-3.2$ ls
001  002  003  004  rename.sh

However it gives me this error (even though it works):

bash-3.2$ ./rename.sh
mv: missing destination file operand after `rename.sh'
Try `mv --help' for more information.
`test 001' -> `001'
`test 002' -> `002'
`test 003' -> `003'
`test 004' -> `004'

Though it works correctly, it would be nice to see where I messed up, I assumed by default it would put the files in the same directory (this is the desired output).

#!/bin/bash
ls | while read -r FILE
do
        mv -v "$FILE" `echo $FILE | awk -F ' ' '{print $2}'`
done

Thanks in advance for helping me correct my incorrect code.

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前事休说 2024-09-23 04:25:35

为什么要使用 ls 和 while 循环的额外过程？只需使用带有 shell 扩展的 for 循环即可。这是首选方式

#!/bin/bash
shopt -s nullglob
for file in *
do
  if [ -f "$file" ];then
    newfile="${file##* }"
    mv "$file" $newfile"
  fi
done

why are you using ls with an extra process to while loop? Just use a for loop with shell expansion. This is preferred way

#!/bin/bash
shopt -s nullglob
for file in *
do
  if [ -f "$file" ];then
    newfile="${file##* }"
    mv "$file" $newfile"
  fi
done

回复收藏 0 原文

护你周全 2024-09-23 04:25:35

邮递员几乎已经有了。对于 rename.sh，awk 命令不返回任何内容，因此实际上 shell 尝试执行以下命令：

mv rename.sh

因此出现错误消息“缺少目标文件”，

您可以通过测试脚本的文件名（硬编码或 $0）来修复此问题，并且仅当 $FILE 等于脚本名称时才执行 mv 命令。

Postman almost has it. For rename.sh, the awk command returns nothing so in effect you have the following command the shell attempts to execute:

mv rename.sh

hence the error message "missing destination file"

you can fix this by testing for the filename of the script, either hardcoded or $0, and executing the mv command only if $FILE does equal the script name.

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亽野灬性zι浪 2024-09-23 04:25:35

我确实喜欢这个，它完美地改变了文件名。你可以像下面这样尝试。

mkdir /root/test; touch my\ file{1..10}

vim rename.sh

#!/bin/bash
ls /root/test| while read -r FILE
do
  mv -v /root/test/"$FILE" /root/test/`echo $FILE | awk -F" " '{print $2}'`
done

 chmod +x rename.sh
./rename.sh

I did like this and it is perfectly changing the filenames. You may try like below.

mkdir /root/test; touch my\ file{1..10}

vim rename.sh

#!/bin/bash
ls /root/test| while read -r FILE
do
  mv -v /root/test/"$FILE" /root/test/`echo $FILE | awk -F" " '{print $2}'`
done

 chmod +x rename.sh
./rename.sh

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