将数组追加到无序列表

发布于 2024-09-15 23:53:59 字数 639 浏览 10 评论 0原文

我试图用这段代码完成的是将数组 alphabet 作为一系列列表项输出到实际标记中的现有无序列表中。我已将数组放入列表项中，但我不知道如何告诉它将自身附加到现有的无序列表

。

var itemsExist = true;
var indexNum = 0;
var unorderedList = document.getElementById('itemList');
var alphabet= new Array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z");

function write_letters(){

    for (i = 0; i < alphabet.length; i++ ) {
        document.write('<li>'  + alphabet[indexNum++] + '</li>');
    }

}

if (itemsExist){
    write_letters();
} else {
    document.write("error!");
}

原文

What I'm trying to accomplish with this code is to output the array alphabet as a series of list items into an existing unordered list in the actual markup. I've got the array into list items, but I can't figure out how to tell it to append itself to an existing unordered list <ul id="itemList"></ul>.

var itemsExist = true;
var indexNum = 0;
var unorderedList = document.getElementById('itemList');
var alphabet= new Array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z");

function write_letters(){

    for (i = 0; i < alphabet.length; i++ ) {
        document.write('<li>'  + alphabet[indexNum++] + '</li>');
    }

}

if (itemsExist){
    write_letters();
} else {
    document.write("error!");
}

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

不弃不离 2024-09-22 23:53:59

不要使用 document.write 来执行此操作。你应该这样做：

function write_letters(){
    var letters = "";

    for (var i = 0; i < alphabet.length; i++ ) {
        //Also I don't understand the purpose of the indexNum variable.
        //letters += "<li>"  + alphabet[indexNum++] + "</li>";
        letters += "<li>"  + alphabet[i] + "</li>";
    }

    document.getElementById("itemList").innerHTML = letters;
}

更正确的方法是使用 DOM（如果你想完全控制即将发生的事情）：

function write_letters(){
    var items = document.getElementById("itemList");

    for (var i = 0; i < alphabet.length; i++ ) {
        var item = document.createElement("li");
        item.innerHTML = alphabet[i];
        items.appendChild(item);
    }

}

Don't use document.write to do it. You should act like this:

function write_letters(){
    var letters = "";

    for (var i = 0; i < alphabet.length; i++ ) {
        //Also I don't understand the purpose of the indexNum variable.
        //letters += "<li>"  + alphabet[indexNum++] + "</li>";
        letters += "<li>"  + alphabet[i] + "</li>";
    }

    document.getElementById("itemList").innerHTML = letters;
}

More proper way is to use DOM (in case you want full control of what's coming on):

function write_letters(){
    var items = document.getElementById("itemList");

    for (var i = 0; i < alphabet.length; i++ ) {
        var item = document.createElement("li");
        item.innerHTML = alphabet[i];
        items.appendChild(item);
    }

}

回复收藏 0 原文

野生奥特曼 2024-09-22 23:53:59

您可以结合使用createElement() 和appendChild() 在另一个HTML 元素中添加新的HTML 元素。下面的代码应该适合您：

<html>

<head>
<title>Script Test</title>
</head>

<body>
    <ul id="itemList"></ul>
</body>

<script>
    var itemsExist = true;
    var indexNum = 0;
    var unorderedList = document.getElementById('itemList');
    var alphabet= new Array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z");
    var myElement;

    function write_letters(){

        for (i = 0; i < alphabet.length; i++ ) {
            // Create the <LI> element
            myElement = document.createElement("LI");
            // Add the letter between the <LI> tags
            myElement.innerHTML = alphabet[indexNum++];
            // Append the <LI> to the bottom of the <UL> element
            unorderedList.appendChild(myElement);
        }
    }

    if (itemsExist){
        write_letters();
    } else {
        document.write("error!");
    }
</script>

</html>

注意脚本如何存在于 body 标记下方。如果您希望脚本按照您编写的方式工作，这一点很重要。否则 document.getElementById('itemList') 将找不到 'itemList' ID。

You can use a combination of createElement() and appendChild() to add new HTML elements within another HTML element. The code below should work for you:

<html>

<head>
<title>Script Test</title>
</head>

<body>
    <ul id="itemList"></ul>
</body>

<script>
    var itemsExist = true;
    var indexNum = 0;
    var unorderedList = document.getElementById('itemList');
    var alphabet= new Array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z");
    var myElement;

    function write_letters(){

        for (i = 0; i < alphabet.length; i++ ) {
            // Create the <LI> element
            myElement = document.createElement("LI");
            // Add the letter between the <LI> tags
            myElement.innerHTML = alphabet[indexNum++];
            // Append the <LI> to the bottom of the <UL> element
            unorderedList.appendChild(myElement);
        }
    }

    if (itemsExist){
        write_letters();
    } else {
        document.write("error!");
    }
</script>

</html>

Note how the script exists below the body tag. This is important if you want your script to work the way you wrote it. Otherwise document.getElementById('itemList') will not find the 'itemList' ID.

回复收藏 0 原文

负佳期 2024-09-22 23:53:59

尽量减少对 DOM 的操作。 unorderedList 上的每个appendChild 都会强制浏览器重新渲染整个页面。使用 documentFragement 进行此类操作。

var frag = document.createDocumentFragment();
for (var i = alphabet.length; i--; ) {
   var li = document.createElement("li");
   li.appendChild(document.createTextNode(alphabet[indexNum++]));
   frag.appendChild(li);
}
unorderedList.appendChild(frag);

因此，只有一个 DOM 操作会强制完全重绘，而不是 alphabet.length 重绘

Try to reduce the actions on the DOM as much as possible. Every appendChild on unorderedList forces the browser to re-render the complete page. Use documentFragement for that sort of action.

var frag = document.createDocumentFragment();
for (var i = alphabet.length; i--; ) {
   var li = document.createElement("li");
   li.appendChild(document.createTextNode(alphabet[indexNum++]));
   frag.appendChild(li);
}
unorderedList.appendChild(frag);

So there will be only one DOM action which forces a complete redraw instead of alphabet.length redraws

回复收藏 0 原文

~没有更多了~