如何通过单个 InputStream 读取多个 ZipEntries
我必须将输入流作为参数传递给第三方库，该库将从输入流中读取完整的内容并完成其工作。
我的问题是，我的一些文件是 Zip 文件 - 具有多个 ZipEntry。据我了解，可以一次读取一个 zipEntry，然后执行 zipInputStream.getNextEntry()，然后再次读取，依此类推。但是，第 3 方库不理解这一点，并且需要单个输入流。 zip 文件的所有 zipEntries 都应作为单个 inputStream 提供。
请赐教我如何去做。我无法使用 ZipFile，因为该文件未存储在本地（在不同的服务器中）。我也无法读取所有 zipEntries 并构造 ByteArrayOutputStream 或字符串，因为文件可能非常大，这会增加内存使用量。
我想要一种方法让一个 inputStream 透明地从单个 zip 文件的多个 zip 条目中读取。
提前致谢， 普拉萨纳
I have to pass an InputStream as a parameter to a 3rd party library, which will read the complete contents from the InputStream and do its job.
My problem is, some of my files are Zip files - with more than one ZipEntry. From what I understand, one can read one zipEntry at a time and then do a zipInputStream.getNextEntry() and then again read and so on. But, the 3rd party library doesn't understand this and expects a single InputStream. All the zipEntries of a zip file should be available as a single inputStream.
Please enlighten me as to how to do it. I cannot use ZipFile as the file is not stored locally (in a different server). I also cannot read all zipEntries and construct a ByteArrayOutputStream or a string as the files can be very big and that will spike memory usage.
I want a way to let one inputStream read from multiple zip entries of a single zip file transparantly.
thanks in advance,
Prasanna
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
我不是专家，但我看到有两种方法可以满足您的要求：
虽然我不会称其为最有效的方法，但相当简单的方法是将它们全部写入缓冲区，然后使用该缓冲区来提供数据输入流。您可以考虑使用 ByteArrayOutputStream，向其提供 ZipEntries，然后使用相同的 buf 创建一个 ByteArrayInputStream
或者，SequenceInputStream 听起来像是您所追求的，但我没有机会详细研究它。
巴拉德
I'm no expert but I see two ways of doing what you are asking for:
While I wouldn't call it the most efficient way, the fairly foolproof method is to write them all to a buffer and then use that buffer to feed an inputstream. You could look into using a ByteArrayOutputStream, feed it your ZipEntries, and then create a ByteArrayInputStream with the same buf
Alternatively the SequenceInputStream sounds like it does what you are after, but I've not had a chance to look into it in much detail.
K.Barad