Django 请求.META

发布于 2024-09-14 20:44:56 字数 524 浏览 2 评论 0原文

如果我想显示 request.META 字典的多个项目：

如何将例如两个放入此字符串格式：

def myurl(request):
    return HttpResponse("You are %s" % request.META['USER'], "Your IP Adress is " % request.META['REMOTE_ADDR'])

不起作用。

另外，我如何显示/提取该词典的选择性项目的任何想法。

如果我想通过模板运行多个。我如何将其插入 html 模板中：

例如

{{request.META }} 。这对所有人都有效吗？如何在每一行中显示它们？

如果我想要例如：

HTTP_COOKIE
QUERY_STRING
HTTP_CONNECTION

显示该 3 的最佳方式是什么？

谢谢！

原文

If I want to display more than one item of the request.META dictionary:

How can I put e.g. two in this string format:

def myurl(request):
    return HttpResponse("You are %s" % request.META['USER'], "Your IP Adress is " % request.META['REMOTE_ADDR'])

does not work.

Also, any ideas how I can display/extract selective items of that dictionary.

If I want to run more than one via a template. How would I insert that in the html template:

e.g.

{{request.META }} . Does that works for all? How can I display them one in each line?

if I want e.g. just:

HTTP_COOKIE
QUERY_STRING
HTTP_CONNECTION

What would be the best way to display that 3 ?

Thanks!

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执手闯天涯 2024-09-21 20:44:56

更新（阅读OP对此答案的评论后）

这里的模板只是一个带有嵌入格式选项的字符串。

1) 它不必被称为 template

def myurl(request):
    place_holders = "You are %(user)s; your IP address is %(ipaddress)s"
    options = dict(user = request.META['USER'], ipaddress = request.META['REMOTE_ADDR'])
    return HttpResponse(place_holders % options)

2) 您可以完全取消它，使其内联。这纯粹是编码风格/偏好的问题。

def myurl(request):
    return HttpResponse("You are %s; your IP address is %s" % (request.META['USER'], request.META['REMOTE_ADDR']))

原始答案

对问题第一部分的快速而肮脏的回答：

def myurl(request):
    template = "You are %(user)s; your IP address is %(ipaddress)s"
    options = dict(user = request.META['USER'], ipaddress = request.META['REMOTE_ADDR'])
    return HttpResponse(template % options)

Update (after reading OP's comment to this answer)

The template here is just a string with embedded format options.

1) It doesn't have to be called template

def myurl(request):
    place_holders = "You are %(user)s; your IP address is %(ipaddress)s"
    options = dict(user = request.META['USER'], ipaddress = request.META['REMOTE_ADDR'])
    return HttpResponse(place_holders % options)

2) You can do away with it altogether make it inline. This is purely a matter of coding style/preference.

def myurl(request):
    return HttpResponse("You are %s; your IP address is %s" % (request.META['USER'], request.META['REMOTE_ADDR']))

Original Answer

Quick and dirty answer to the first part of your question:

def myurl(request):
    template = "You are %(user)s; your IP address is %(ipaddress)s"
    options = dict(user = request.META['USER'], ipaddress = request.META['REMOTE_ADDR'])
    return HttpResponse(template % options)

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哭泣的笑容 2024-09-21 20:44:56

使用 RequestContext：

from django.template import RequestContext
from django.shortcuts import render_to_response


def myurl(request):
    return render_to_response('template.html', {},
                               context_instance=RequestContext(request))

然后您将可以访问 request.META 及其包含的所有内容。您可以使用调试模板标签来打印您的上下文。

Use RequestContext:

from django.template import RequestContext
from django.shortcuts import render_to_response


def myurl(request):
    return render_to_response('template.html', {},
                               context_instance=RequestContext(request))

You will then have access to request.META and everything it contains. You may use the debug template tag to print your context.

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