如何更改（以及稍后恢复）文本框中的默认上下文菜单

发布于 2024-09-14 18:52:33 字数 225 浏览 2 评论 0原文

我想更改默认的文本框上下文菜单，所以我创建了自己的菜单，并像这样分配了它们

texbox.ContextMenu = myContextMenu

，但是我不知道如何恢复默认的文本框菜单（在运行时）。仅当我用鼠标右键单击文本框（同时按住 Control 按钮）时，我才需要显示 myContextMenu。在其他情况下，我需要显示默认的文本框上下文菜单。是否可以？？

原文

I wanted to change default textbox context menu, so I created my own menu and them I assigned it like that

texbox.ContextMenu = myContextMenu

However I don't know how to restore default textbox menu (in a runtime). I need myContextMenu to show only when I click textbox with right mouse button (while holding Control button). In other cases I need default textbox contextmenu to show.
Is it possible ??

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傲鸠 2024-09-21 18:52:33

以下是微软给出的示例：

http://msdn.microsoft.com/en -us/library/ms750420.aspx

郑重声明，以下是使用 WinForms 执行此操作的方法：

public partial class TextBoxContextMenuDemo : Form
{
    ContextMenu mnuContextDefault;
    ContextMenu mnuContextAlt;

    MenuItem mnuItmAltMenuTest;

    public TextBoxContextMenuDemo()
    {
        InitializeComponent();
        InitializeAltContextMenu();
    }

    private void InitializeAltContextMenu()
    {
        mnuContextDefault = new ContextMenu();
        mnuContextDefault = this.TextBox1.ContextMenu;

        mnuItmAltMenuTest = new MenuItem();
        mnuItmAltMenuTest.Index = -1;
        mnuItmAltMenuTest.Text = "Test Menu Item";
        mnuItmAltMenuTest.Click += new System.EventHandler(this.mnuItmAltMenuTest_Click);

        mnuContextAlt = new ContextMenu();
        mnuContextAlt.MenuItems.Add(mnuItmAltMenuTest);
    }

    private void TextBox1_MouseDown(object sender, MouseEventArgs e)
    {
        if (e.Button == MouseButtons.Right)
        {
            if ((Control.ModifierKeys == Keys.Control))
            {
                this.TextBox1.ContextMenu = mnuContextAlt;
                TextBox1.ContextMenu.Show(TextBox1, new Point(e.X, e.Y));
            }
            else
            {
                this.TextBox1.ContextMenu = mnuContextDefault;
            }
        }
    }

    private void mnuItmAltMenuTest_Click(object sender, System.EventArgs e)
    {
        MessageBox.Show("You clicked the alternate test menu item!");
    }
}

HTH！

Here is the example given by Microsoft:

http://msdn.microsoft.com/en-us/library/ms750420.aspx

For the record, here is the way to do this using WinForms:

public partial class TextBoxContextMenuDemo : Form
{
    ContextMenu mnuContextDefault;
    ContextMenu mnuContextAlt;

    MenuItem mnuItmAltMenuTest;

    public TextBoxContextMenuDemo()
    {
        InitializeComponent();
        InitializeAltContextMenu();
    }

    private void InitializeAltContextMenu()
    {
        mnuContextDefault = new ContextMenu();
        mnuContextDefault = this.TextBox1.ContextMenu;

        mnuItmAltMenuTest = new MenuItem();
        mnuItmAltMenuTest.Index = -1;
        mnuItmAltMenuTest.Text = "Test Menu Item";
        mnuItmAltMenuTest.Click += new System.EventHandler(this.mnuItmAltMenuTest_Click);

        mnuContextAlt = new ContextMenu();
        mnuContextAlt.MenuItems.Add(mnuItmAltMenuTest);
    }

    private void TextBox1_MouseDown(object sender, MouseEventArgs e)
    {
        if (e.Button == MouseButtons.Right)
        {
            if ((Control.ModifierKeys == Keys.Control))
            {
                this.TextBox1.ContextMenu = mnuContextAlt;
                TextBox1.ContextMenu.Show(TextBox1, new Point(e.X, e.Y));
            }
            else
            {
                this.TextBox1.ContextMenu = mnuContextDefault;
            }
        }
    }

    private void mnuItmAltMenuTest_Click(object sender, System.EventArgs e)
    {
        MessageBox.Show("You clicked the alternate test menu item!");
    }
}

HTH!

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