给定一定数量的小数位的纬度/经度，如何判断覆盖的面积（以米为单位）？
如果我有一个以纬度和经度指定的位置，那么它可以覆盖一个盒子，具体取决于该位置的精度有多少位。
例如，给定位置为北纬 55.0°，西经 3.0°（即精确到小数点后 1 位），并假设截断（而不是四舍五入），这可以涵盖 55.01° 到 55.09° 之间的任何位置。这将覆盖此框中的区域： http://www.openstreetmap.org/?minlat=55.0&maxlat=55.1&maxlon=-3.0&minlon=-3.1&box=yes
有吗无论如何计算那个盒子的面积？我只想执行一次，因此一个提供此计算的简单网站就足够了。
我想这样做的主要原因是因为我的位置有非常高的小数位数，并且我想看看它有多精确。
If i have a position specified in latitude and longitude, then it can cover a box, depending on how many digits of accuracy are in the position.
For example, given a position of 55.0° N, 3.0° W (i.e. to 1 decimal place), and assuming a truncation (as opposed to rounding), this could cover anything that's 55.01° to 55.09°. This would cover the area in this box: http://www.openstreetmap.org/?minlat=55.0&maxlat=55.1&maxlon=-3.0&minlon=-3.1&box=yes
Is there anyway to calculate the area of that box? I only want to do this once, so a simple website that provides this calculation would suffice.
The main reason I want to do this is because I have a position to a very high number of decimal places, and I want to see how precise it is.
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虽然地球并不完全是球形的，但您可以将其视为球形来进行这些计算。
北/南计算相对简单，因为两极之间有 180°，距离为 20,014 公里 (来源）因此 1 度 == 20014/180 = 111.19 公里。
东/西计算比较困难，因为它取决于纬度。赤道距离为 40,076 公里（来源），因此 1 度 = 40076/360 = 111.32 公里。两极的周长（根据定义）为 0 公里。因此，您可以通过三角函数计算任意纬度的周长（
circumference * sin(latitude)）。While the Earth isn't exactly spherical you can treat it as such for these calculations.
The North/South calculation is relatively simple as there are 180° from pole to pole and the distance is 20,014 km (Source) so one degree == 20014/180 = 111.19 km.
The East/West calculation is more difficult as it depends on the latitude. The Equatorial distance is 40,076 km (Source) so one degree = 40076/360 = 111.32 km. The circumference at the poles is (by definition) 0 km. So you can calculate the circumference at any latitude by trigonometry (
circumference * sin(latitude)).我写了一个在线测地线面积计算器，可以在
http://geographiclib.sf.net/cgi-bin/Planimeter。输入四个
盒子的角（逆时针），它会给出它的面积。
I have written an online geodesic area calculator which is available at
http://geographiclib.sf.net/cgi-bin/Planimeter. Enter in the four
corners of your box (counter clockwise) and it will give its area.