如何更改 Android 中选择的边框颜色(形状)?
我使用 LinearLayout (bg:圆角矩形)围绕可绘制对象设置了边框。
可绘制对象和边框用作选项卡视图。我想在选择选项卡时更改其边框颜色。
我该怎么做?
颜色状态列表似乎不起作用,因为选择的视图不是形状(即边框)而是选项卡。可绘制状态列表似乎也不起作用,因为我试图在视图之间旋转,而不是可绘制对象。此外,我找不到任何此类“onSelectedListener”......
I've a border set around a drawable using LinearLayout (bg: rounded rectangle).
The drawable and the border is used as a tab view. I'd like to change the border color of the tab when it is selected.
How can I do this?
Color state list doesn't seem to work as the view being selected is not the shape (i.e border) but the tab. Drawable state list doesn't seem to work either as I'm trying to swivel between views, not drawables. Moreover, I can't find any "onSelectedListener" of the sort...
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您需要创建一个 OnClickListener 来处理点击,并让它更改适当的背景:
You need to make an
OnClickListener
to handle clicks, and get it to change the appropriate background:解决方案是在 TabHost 中调用 setOnTabChangeListener,然后手动更改所有内容。
The solution is to call setOnTabChangeListener in the TabHost and then change everything manually.