Django：输入图像文件的小写文件名

发布于 2024-09-14 00:38:35 字数 273 浏览 1 评论 0原文

我有一个模型：

class Foo(models.Model):
    poster = models.ImageField(u"Poster", upload_to='img')

我正在使用管理员上传海报并保存 Foo 对象。我现在需要找到一种方法在保存之前将文件名小写。例如 POSTER.png 或 Poster.png 或 poster.PNG 应小写为 poster.png。

实现这一目标的最简单方法是什么？

原文

I have a model:

class Foo(models.Model):
    poster = models.ImageField(u"Poster", upload_to='img')

I'm using the admin to upload posters and save Foo objects. I now need to find a way to lowercase the filename before save. For instance POSTER.png or Poster.png or poster.PNG should be lowercased to poster.png.

What would be the easiest way to achieve this?

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很快妥协 2024-09-21 00:38:35

FileField.upload_to也可以是可调用的，根据文档中的注释：

这也可以是可调用的，例如函数，将调用该函数来获取上传路径，包括文件名。此可调用必须能够接受两个参数，并返回要传递到存储系统的 Unix 样式路径（带有正斜杠）。将传递的两个参数是：

由于 ImageField继承了 FileField 的所有属性和方法，我认为您可以使用：

def update_filename(instance, filename):
    path_you_want_to_upload_to = "img"
    return os.path.join(path_you_want_to_upload_to, filename.lower())

class Foo(models.Model):
    poster = models.ImageField(u"Poster", upload_to=update_filename)

FileField.upload_to may also be a callable, per this comment in the documentation:

This may also be a callable, such as a function, which will be called to obtain the upload path, including the filename. This callable must be able to accept two arguments, and return a Unix-style path (with forward slashes) to be passed along to the storage system. The two arguments that will be passed are:

Since ImageField inherits all its attributes and methods from FileField, I think you could use:

def update_filename(instance, filename):
    path_you_want_to_upload_to = "img"
    return os.path.join(path_you_want_to_upload_to, filename.lower())

class Foo(models.Model):
    poster = models.ImageField(u"Poster", upload_to=update_filename)

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