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基于 RabbitMQ 消息消费 ID（c# API）

发布于 2024-09-13 23:49:55 字数 125 浏览 12 评论 0原文

我想发布/生成带有某些消息ID的消息，就像每条消息都有一个特定的ID一样。

在消费者端，我想通过提供ID来检索消息。假设我们有多个消费者，那么每个消费者应该只获取他们通过消息 ID 请求的消息。（我希望我足够清楚）。

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眼中杀气 2024-09-20 23:49:56

虽然这不是设计使然，最好使用数据库，但有一种方法可以使用rabbitmq来做到这一点：

使用 id 发布消息：

var message = "some message";
var messageId = Guid.NewGuid().ToString();
var factory = new ConnectionFactory { HostName = "localhost" };

using (var connection = factory.CreateConnection())
using (var channel = connection.CreateModel())
{
    IBasicProperties props = channel.CreateBasicProperties();
    props.MessageId = messageId;

    byte[] messageBodyBytes = Encoding.UTF8.GetBytes(message);

    channel.BasicPublish("", "queueName", true, props, messageBodyBytes);
}

通过 id 获取消息：

var messageId = "id";
var factory = new ConnectionFactory { HostName = "localhost" };

using (var connection = _factory.CreateConnection())
using (var channel = connection.CreateModel())
{
    var queueDeclareResponse = channel.QueueDeclare("queueName", true, true, false, null);

    for (int i = 0; i < queueDeclareResponse.MessageCount; i++)
    {
        var result = channel.BasicGet("queueName", false);
        var id = result.BasicProperties.MessageId;

        if (id == messageId)
        {
            var body = result.Body;
            var message = Encoding.UTF8.GetString(body);

            //Do something with the message

            channel.BasicAck(result.DeliveryTag, false);
            break;
        }
    }
}

处置通道后，所有未确认的消息都将重新排队。

Although its not by design and its better to use a database for that there is a way to do this using rabbitmq:

Publish a message with id:

var message = "some message";
var messageId = Guid.NewGuid().ToString();
var factory = new ConnectionFactory { HostName = "localhost" };

using (var connection = factory.CreateConnection())
using (var channel = connection.CreateModel())
{
    IBasicProperties props = channel.CreateBasicProperties();
    props.MessageId = messageId;

    byte[] messageBodyBytes = Encoding.UTF8.GetBytes(message);

    channel.BasicPublish("", "queueName", true, props, messageBodyBytes);
}

Get a message by id:

var messageId = "id";
var factory = new ConnectionFactory { HostName = "localhost" };

using (var connection = _factory.CreateConnection())
using (var channel = connection.CreateModel())
{
    var queueDeclareResponse = channel.QueueDeclare("queueName", true, true, false, null);

    for (int i = 0; i < queueDeclareResponse.MessageCount; i++)
    {
        var result = channel.BasicGet("queueName", false);
        var id = result.BasicProperties.MessageId;

        if (id == messageId)
        {
            var body = result.Body;
            var message = Encoding.UTF8.GetString(body);

            //Do something with the message

            channel.BasicAck(result.DeliveryTag, false);
            break;
        }
    }
}

After channel is disposed all messages that was not acked will requeue.

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