NSSting * 和 .plist 中的 \n
代码：
NSString *strDirect = @"Dummy\nMessage";
NSString *strBundle = [[[NSBundle mainBundle] infoDictionary] objectForKey:@"MessageDummy"];
NSLog(@"Direct: %@", strDirect);
NSLog(@"Bundle: %@", strBundle);
其中MessageDummy是.plist文件中的字符串类型值Dummy\nMessage。即：
<key>MessageDummy</key>
<string>Dummy\nMessage</string>
输出：
2010-08-09 11:49:18.641 Plan[15558:207] Direct: Dummy
Message
2010-08-09 11:49:18.642 Plan[15558:207] Bundle: Dummy\nMessage
\n 在 NSString * 中受到尊重，但在从 objectForKey 返回时则不然。如何使 objectForKey 的返回值的行为与 NSString * 相同？
Code:
NSString *strDirect = @"Dummy\nMessage";
NSString *strBundle = [[[NSBundle mainBundle] infoDictionary] objectForKey:@"MessageDummy"];
NSLog(@"Direct: %@", strDirect);
NSLog(@"Bundle: %@", strBundle);
where MessageDummy is a string type value Dummy\nMessage in the .plist file. i.e.:
<key>MessageDummy</key>
<string>Dummy\nMessage</string>
Output:
2010-08-09 11:49:18.641 Plan[15558:207] Direct: Dummy
Message
2010-08-09 11:49:18.642 Plan[15558:207] Bundle: Dummy\nMessage
\n is honored in NSString * but not when returned from objectForKey. How can I make the return value of objectForKey behaves same as the NSString *?
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问题是，当您尝试检索它时，“\n”被视为“\\n”（\ 用 \\ 转义）。解决这个问题的方法是，不要使用
use:
希望这会有所帮助。
The problem is that while "\n" is treated as "\\n" while you are trying to retrieve it (\ is escaped with \\). The work around for this is, instead of using
use:
Hope this helps.
除了 Madhup 的答案之外，可能值得指出的是“\n”是一个 C 编译器构造，一种用于传达在源代码中定义的文字字符串中包含换行符的愿望的机制。
Plist 以 XML 格式存储，它有自己的数据格式、转义规则等。
两者之间没有关系，您不应该期望两者之间有类似的行为。
In addition to Madhup's answer, its probably worth pointing out that "\n" is a C-compiler construct, a mechanism for communicating a desire to include a newline in a literal string defined in source code.
Plists are stored in XML format which has its own data format, escaping rules, etc.
There is no relationship between the two, and you should not expect similiar behaviour between the two.