使用 boost::serialization 序列化为 XML
这是一个新手问题。我试图将一些对象序列化为 XML，但生成的 XML 包含 boost 序列化签名、版本信息、类 ID 等。我不需要。有没有办法在不后处理 xml 消息的情况下摆脱它们？
#include <fstream>
#include <iostream>
#include <boost/archive/xml_iarchive.hpp>
#include <boost/archive/xml_oarchive.hpp>
using namespace std;
class Test {
private:
friend class boost::serialization::access;
template<class Archive> void serialize(Archive & ar,
const unsigned int version) {
ar & BOOST_SERIALIZATION_NVP(a);
ar & BOOST_SERIALIZATION_NVP(b);
ar & BOOST_SERIALIZATION_NVP(c);
}
int a;
int b;
float c;
public:
inline Test(int a, int b, float c) {
this->a = a;
this->b = b;
this->c = c;
}
};
int main() {
std::ofstream ofs("filename.xml");
Test* test = new Test(1, 2, 3.3);
boost::archive::xml_oarchive oa(ofs);
oa << BOOST_SERIALIZATION_NVP(test);
return 0;
}
结果是：
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<!DOCTYPE boost_serialization (View Source for full doctype...)>
<boost_serialization signature="serialization::archive" version="6">
<test class_id="0" tracking_level="1" version="0" object_id="_0">
<a>1</a>
<b>2</b>
<c>3.3</c>
</test>
</boost_serialization>
不过，我会将这些消息序列化为字符串，并将它们发送到期望消息如下所示的系统。
<test>
<a>1</a>
<b>2</b>
<c>3.3</c>
</test>
有没有办法在没有签名的情况下序列化xml？
This is a newbie question. I am trying to serialize some objects to XML, but the resulting XML contains a boost serialization signature, version information, class id, ...etc. that I do not need. Is there a way to get rid of them without post-processing the xml message?
#include <fstream>
#include <iostream>
#include <boost/archive/xml_iarchive.hpp>
#include <boost/archive/xml_oarchive.hpp>
using namespace std;
class Test {
private:
friend class boost::serialization::access;
template<class Archive> void serialize(Archive & ar,
const unsigned int version) {
ar & BOOST_SERIALIZATION_NVP(a);
ar & BOOST_SERIALIZATION_NVP(b);
ar & BOOST_SERIALIZATION_NVP(c);
}
int a;
int b;
float c;
public:
inline Test(int a, int b, float c) {
this->a = a;
this->b = b;
this->c = c;
}
};
int main() {
std::ofstream ofs("filename.xml");
Test* test = new Test(1, 2, 3.3);
boost::archive::xml_oarchive oa(ofs);
oa << BOOST_SERIALIZATION_NVP(test);
return 0;
}
results in:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<!DOCTYPE boost_serialization (View Source for full doctype...)>
<boost_serialization signature="serialization::archive" version="6">
<test class_id="0" tracking_level="1" version="0" object_id="_0">
<a>1</a>
<b>2</b>
<c>3.3</c>
</test>
</boost_serialization>
I'll be serializing these messages to strings, though, and sending them to systems that expect a message to look like this.
<test>
<a>1</a>
<b>2</b>
<c>3.3</c>
</test>
Is there a way to serialize xml without the signature?
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标志 no_header 消除标题行
以下宏消除属性
the flag no_header eliminates the heading lines
the following macro eliminates the attributes
这不是
boost::serialization应该使用的用途。如果您希望生成特定类型的 XML，最好使用 XML 生成器，例如 Xerces （是的，它到处都写着“解析器”，但它也会写入 XML）。That is not what
boost::serializationshould be used for. If you're looking to generate a specific type of XML, better use an XML generator like Xerces (yes, it says "parser" everywhere, but it'll also write XML).