将摘要转换为 base10

发布于 2024-09-13 07:12:53 字数 442 浏览 7 评论 0原文

是否可以采用类似创建的摘要

my $digest  = Digest::SHA->new('sha1')->add('hello')->digest;

，然后将 $digest 转换为 base10（而不是十六进制或 base64？），或者您可以将十六进制摘要拆分为 5 块然后将它们转换为整数？那行得通吗？试图想出一种将摘要存储为整数的方法（是的，我知道有人会认为我疯了或愚蠢，可能两者兼而有之）。

更新

理论上，我应该能够获取最终编码的整数输出，并根据需要反转并重新编码为十六进制和 base64。

原文

Is it possible to take a digest created like

my $digest  = Digest::SHA->new('sha1')->add('hello')->digest;

and then convert $digest to base10 (instead of hex or base64?) or could you split a hexdigest into 5 pieces and then convert those into integers? would that work? Trying to come up with a way to store the digest as integers (yes I know someone is going to think I'm crazy or stupid, probably both).

update

In theory I should be able to take the final encoded integer output and reverse and reencode to hex and base64 as needed.

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甜｀诱少女 2024-09-20 07:12:53

如果无论你要去哪里都可以毫不犹豫地处理任意精度的整数（是的，很奇怪，但你永远不知道），那么你可以将其编码为单个整数；）

$ re.pl
$ use Digest::SHA; use Math::BigInt;

$ my $hex = Digest::SHA->new("SHA-1")->add("hello")->hexdigest;
aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
$ Math::BigInt->from_hex("0x" . $hex)->bstr
975987071262755080377722350727279193143145743181
$ Math::BigInt->new("975987071262755080377722350727279193143145743181")->as_hex
0xaaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d

If wherever you're going can handle arbitrary-precision integers without flinching (yeah, unikely, but you never know), then you can just encode it as a single integer ;)

$ re.pl
$ use Digest::SHA; use Math::BigInt;

$ my $hex = Digest::SHA->new("SHA-1")->add("hello")->hexdigest;
aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
$ Math::BigInt->from_hex("0x" . $hex)->bstr
975987071262755080377722350727279193143145743181
$ Math::BigInt->new("975987071262755080377722350727279193143145743181")->as_hex
0xaaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d

回复收藏 0 原文

萌梦深 2024-09-20 07:12:53

我认为 pack & unpack 可能会更有效：

use Digest::SHA;

my $digest  = Digest::SHA->new('sha1')->add('hello')->digest;
my @ints = unpack('N*', $digest);
print "@ints\n";

my $redone = pack('N*', @ints);

print "match\n" if $digest eq $redone;

my $hexdigest = sprintf '%08x' x @ints, @ints;
print "$hexdigest\n";
printf "%s\n", Digest::SHA->new('sha1')->add('hello')->hexdigest;

use MIME::Base64 'encode_base64';
my $b64digest = encode_base64(pack('N*', @ints));
print $b64digest;
printf "%s\n", Digest::SHA->new('sha1')->add('hello')->b64digest;

输出：

2868168221 3703957666 3669941775 994585817 2930328397
match
aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
qvTGHdzF6KLavt4PO0gs2a6pQ00=
qvTGHdzF6KLavt4PO0gs2a6pQ00

请注意，MIME::Base64 会填充结果，而 b64digest 方法则不会。但如果需要的话，删除尾随的 = 很容易。

I think pack & unpack will probably be more efficient:

use Digest::SHA;

my $digest  = Digest::SHA->new('sha1')->add('hello')->digest;
my @ints = unpack('N*', $digest);
print "@ints\n";

my $redone = pack('N*', @ints);

print "match\n" if $digest eq $redone;

my $hexdigest = sprintf '%08x' x @ints, @ints;
print "$hexdigest\n";
printf "%s\n", Digest::SHA->new('sha1')->add('hello')->hexdigest;

use MIME::Base64 'encode_base64';
my $b64digest = encode_base64(pack('N*', @ints));
print $b64digest;
printf "%s\n", Digest::SHA->new('sha1')->add('hello')->b64digest;

Output:

2868168221 3703957666 3669941775 994585817 2930328397
match
aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
qvTGHdzF6KLavt4PO0gs2a6pQ00=
qvTGHdzF6KLavt4PO0gs2a6pQ00

Note that MIME::Base64 pads the result, and the b64digest method doesn't. But it's easy enough to strip off the trailing = if you need to.

回复收藏 0 原文

请别遗忘我 2024-09-20 07:12:53

也许是这样的？

#!/usr/bin/perl

use strict; use warnings;
use Digest::SHA;
use YAML;

my $digest  = Digest::SHA->new('sha1')->add('hello')->hexdigest;
print "$digest\n";
print Dump [ map { [$_, hex] } $digest =~ /([[:xdigit:]]{8})/g ];

输出：

aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
---
-
  - aaf4c61d
  - 2868168221
-
  - dcc5e8a2
  - 3703957666
-
  - dabede0f
  - 3669941775
-
  - 3b482cd9
  - 994585817
-
  - aea9434d
  - 2930328397

Something like this, maybe?

#!/usr/bin/perl

use strict; use warnings;
use Digest::SHA;
use YAML;

my $digest  = Digest::SHA->new('sha1')->add('hello')->hexdigest;
print "$digest\n";
print Dump [ map { [$_, hex] } $digest =~ /([[:xdigit:]]{8})/g ];

Output:

aaf4c61ddcc5e8a2dabede0f3b482cd9aea9434d
---
-
  - aaf4c61d
  - 2868168221
-
  - dcc5e8a2
  - 3703957666
-
  - dabede0f
  - 3669941775
-
  - 3b482cd9
  - 994585817
-
  - aea9434d
  - 2930328397

回复收藏 0 原文

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