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如何清除我的 Jenkins/Hudson 构建历史记录？

发布于 2024-09-13 06:43:05 字数 66 浏览 6 评论 0原文

我最近更新了我的哈德森构建之一的配置。构建历史记录不同步。有没有办法清除我的构建历史记录？

请并谢谢你

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月光色 2024-09-20 06:43:05

使用脚本控制台（管理 Jenkins > 脚本控制台）和类似此脚本的内容来批量删除作业的构建历史记录 https://github.com/jenkinsci/jenkins-scripts/blob/master/scriptler/bulkDeleteBuilds.groovy

该脚本假设您只想删除一系列构建。要删除给定作业的所有构建，请使用此命令（已测试）：

// change this variable to match the name of the job whose builds you want to delete
def jobName = "Your Job Name"
def job = Jenkins.instance.getItem(jobName)

job.getBuilds().each { it.delete() }
// uncomment these lines to reset the build number to 1:
//job.nextBuildNumber = 1
//job.save()

Use the script console (Manage Jenkins > Script Console) and something like this script to bulk delete a job's build history https://github.com/jenkinsci/jenkins-scripts/blob/master/scriptler/bulkDeleteBuilds.groovy

That script assumes you want to only delete a range of builds. To delete all builds for a given job, use this (tested):

// change this variable to match the name of the job whose builds you want to delete
def jobName = "Your Job Name"
def job = Jenkins.instance.getItem(jobName)

job.getBuilds().each { it.delete() }
// uncomment these lines to reset the build number to 1:
//job.nextBuildNumber = 1
//job.save()

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惟欲睡 2024-09-20 06:43:05

此答案适用于 Jenkins

转到 Jenkins 主页 → 管理 Jenkins → 脚本控制台
在那里运行以下脚本。将 copy_folder 更改为您的项目名称

代码：

def jobName = "copy_folder"
def job = Jenkins.instance.getItem(jobName)
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

我的帖子

This answer is for Jenkins

Go to your Jenkins home page → Manage Jenkins → Script Console
Run the following script there. Change copy_folder to your project name

Code:

def jobName = "copy_folder"
def job = Jenkins.instance.getItem(jobName)
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

My post

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徒留西风 2024-09-20 06:43:05

如果您单击管理 Hudson / 从磁盘重新加载配置，Hudson 将重新加载所有构建历史数据。

如果磁盘上的数据混乱，您需要转到 %HUDSON_HOME%\jobs\<projectname>目录并恢复构建目录，因为它们应该是。然后重新加载配置数据。

如果您只是询问如何删除所有构建历史记录，则可以通过 UI 将构建一一删除（如果只有少数），或者转到 %HUDSON_HOME%\jobs\<projectname>目录并删除那里的所有子目录——它们对应于构建。
然后重新启动服务以使更改生效。

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无悔心 2024-09-20 06:43:05

这是另一个选项：使用 cURL 删除构建。

$ curl -X POST http://jenkins-host.tld:8080/jenkins/job/myJob/[1-56]/doDeleteAll

上面删除了作业 myJob 的构建 #1 到 #56。

如果在 Jenkins 实例上启用了身份验证，则必须提供用户名和 API 令牌，如下所示：

$ curl -u userName:apiToken -X POST http://jenkins-host.tld:8080/jenkins/job/myJob/[1-56]/doDeleteAll

必须从 Jenkins 中的 /me/configure 页面获取 API 令牌。只需单击“显示 API 令牌...”按钮即可显示用户名和 API 令牌。

编辑：可能需要将上面 URL 中的 doDeleteAll 替换为 doDelete 才能完成此操作，具体取决于所使用的 Jenkins 的配置或版本。

Here is another option: delete the builds with cURL.

$ curl -X POST http://jenkins-host.tld:8080/jenkins/job/myJob/[1-56]/doDeleteAll

The above deletes build #1 to #56 for job myJob.

If authentication is enabled on the Jenkins instance, a user name and API token must be provided like this:

$ curl -u userName:apiToken -X POST http://jenkins-host.tld:8080/jenkins/job/myJob/[1-56]/doDeleteAll

The API token must be fetched from the /me/configure page in Jenkins. Just click on the "Show API Token..." button to display both the user name and the API token.

Edit: one might have to replace doDeleteAll by doDelete in the URLs above to make this work, depending on the configuration or the version of Jenkins used.

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浮光之海 2024-09-20 06:43:05

以下是如何使用 Jenkins 脚本删除所有作业的所有构建......。

def jobs = Jenkins.instance.projects.collect { it } 
jobs.each { job -> job.getBuilds().each { it.delete() }}

Here is how to delete ALL BUILDS FOR ALL JOBS...... using the Jenkins Scripting.

def jobs = Jenkins.instance.projects.collect { it } 
jobs.each { job -> job.getBuilds().each { it.delete() }}

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东风软 2024-09-20 06:43:05

您可以临时修改项目配置以仅保存最后 1 个构建，重新加载配置（这应该废弃旧的构建），然后再次将配置设置更改为您想要的值。

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深府石板幽径 2024-09-20 06:43:05

这是可用的最佳选择。

Jenkins.instance.getAllItems(AbstractProject.class).each {it -> Jenkins.instance.getItemByFullName(it.fullName).builds.findAll { it.number > 0 }.each { it.delete() } }

此代码将删除所有 Jenkins 作业构建历史记录。

This one is the best option available.

Jenkins.instance.getAllItems(AbstractProject.class).each {it -> Jenkins.instance.getItemByFullName(it.fullName).builds.findAll { it.number > 0 }.each { it.delete() } }

This code will delete all Jenkins Job build history.

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柠檬心 2024-09-20 06:43:05

如果你想清除MultiBranchProject的构建历史（例如管道），
转到 Jenkins 主页 → 管理 Jenkins → 脚本控制台并运行以下脚本：

def projectName = "ProjectName"
def project = Jenkins.instance.getItem(projectName)
def jobs = project.getItems().each {
  def job = it
  job.getBuilds().each { it.delete() }
  job.nextBuildNumber = 1
  job.save()
}

If you want to clear the build history of MultiBranchProject (e.g. pipeline),
go to your Jenkins home page → Manage Jenkins → Script Console and run the following script:

def projectName = "ProjectName"
def project = Jenkins.instance.getItem(projectName)
def jobs = project.getItems().each {
  def job = it
  job.getBuilds().each { it.delete() }
  job.nextBuildNumber = 1
  job.save()
}

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极度宠爱 2024-09-20 06:43:05

使用脚本控制台。

如果作业被分组，可以给它一个带有正斜杠的全名：

getItemByFullName("folder_name/job_name") 
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

或者像这样遍历层次结构：

def folder = Jenkins.instance.getItem("folder_name")
def job = folder.getItem("job_name")
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

Using Script Console.

In case the jobs are grouped it's possible to either give it a full name with forward slashes:

getItemByFullName("folder_name/job_name") 
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

or traverse the hierarchy like this:

def folder = Jenkins.instance.getItem("folder_name")
def job = folder.getItem("job_name")
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

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浅唱ヾ落雨殇 2024-09-20 06:43:05

直接从文件系统删除并不安全。您可以运行以下脚本来删除所有作业中的所有构建（递归地）。

def numberOfBuildsToKeep = 10
Jenkins.instance.getAllItems(AbstractItem.class).each {
  if( it.class.toString() != "class com.cloudbees.hudson.plugins.folder.Folder" && it.class.toString() != "class org.jenkinsci.plugins.workflow.multibranch.WorkflowMultiBranchProject") {
    println it.name
    builds = it.getBuilds()
    for(int i = numberOfBuildsToKeep; i < builds.size(); i++) {
        builds.get(i).delete()
      println "Deleted" + builds.get(i)
    }
  }
}

Deleting directly from file system is not safe. You can run the below script to delete all builds from all jobs ( recursively ).

def numberOfBuildsToKeep = 10
Jenkins.instance.getAllItems(AbstractItem.class).each {
  if( it.class.toString() != "class com.cloudbees.hudson.plugins.folder.Folder" && it.class.toString() != "class org.jenkinsci.plugins.workflow.multibranch.WorkflowMultiBranchProject") {
    println it.name
    builds = it.getBuilds()
    for(int i = numberOfBuildsToKeep; i < builds.size(); i++) {
        builds.get(i).delete()
      println "Deleted" + builds.get(i)
    }
  }
}

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浅唱々樱花落 2024-09-20 06:43:05

转到“管理詹金斯”> “脚本控制台”

运行如下：

def jobName = "build_name"  
def job = Jenkins.instance.getItem(jobName)  
job.getBuilds().each { it.delete() }  
job.save()

Go to "Manage Jenkins" > "Script Console"

Run below:

def jobName = "build_name"  
def job = Jenkins.instance.getItem(jobName)  
job.getBuilds().each { it.delete() }  
job.save()

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等待圉鍢 2024-09-20 06:43:05

清理构建的另一种简单方法是在作业结束时添加“丢弃旧插件”。设置要保存的最大构建数，然后再次运行作业：

https://wiki.jenkins-ci.org/display/JENKINS/Discard+Old+Build+plugin

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神妖 2024-09-20 06:43:05

转到 %HUDSON_HOME%\jobs\ 删除 builds 目录并删除 lastStable、lastSuccessful 链接，然后删除 nextBuildNumber 文件。

完成上述步骤后，从 UI 转到以下链接
詹金斯->管理 Jenkins ->从磁盘重新加载配置

它将根据您的需要进行

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阪姬 2024-09-20 06:43:05

如果使用脚本控制台方法，请尝试使用以下方法来考虑作业是否分组到文件夹容器中。

def jobName = "Your Job Name"
def job = Jenkins.instance.getItemByFullName(jobName)

或者

def jobName = "My Folder/Your Job Name
def job = Jenkins.instance.getItemByFullName(jobName)

If using the Script Console method then try using the following instead to take into account if jobs are being grouped into folder containers.

def jobName = "Your Job Name"
def job = Jenkins.instance.getItemByFullName(jobName)

def jobName = "My Folder/Your Job Name
def job = Jenkins.instance.getItemByFullName(jobName)

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记忆之渊 2024-09-20 06:43:05

导航至：%JENKINS_HOME%\jobs\jobName

打开文件“nextBuildNumber”并更改数字。之后重新加载 Jenkins 配置。注意：“nextBuildNumber”文件包含 Jenkins 将使用的下一个版本号。

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鯉魚旗 2024-09-20 06:43:05

在 Linux 上的 jenkins 2.293 上进行了测试。它将删除所有构建日志，但不会删除相关构建号

cd /var/lib/jenkins/jobs
find . -name "builds" -exec rm -rf {} \;

请小心使用此命令，因为它会对每个查找结果执行rm -rf。您可以先执行此命令来验证结果是否仅在您作业的builds文件夹中

find . -name "builds"

Tested on jenkins 2.293 over linux. It will remove all the build logs but not the corellative build number

cd /var/lib/jenkins/jobs
find . -name "builds" -exec rm -rf {} \;

Be careful with this command because it executes a rm -rf on each find result. You could exec this first to validate if the result are only the builds folder of you jobs

find . -name "builds"

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孤云独去闲 2024-09-20 06:43:05

如果您正在寻找文件夹内有作业的解决方案，您可以使用getItemByFullName函数。它还支持文件夹和作业名称中的空格。

def jobName = "folder_name/job_name"
def job = Jenkins.instance.getItemByFullName(jobName)
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

If you are looking for a solution where you have job inside a Folder you can use getItemByFullName function. It also supports white space in folder and job name.

def jobName = "folder_name/job_name"
def job = Jenkins.instance.getItemByFullName(jobName)
job.getBuilds().each { it.delete() }
job.nextBuildNumber = 1
job.save()

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作业与我同在 2024-09-20 06:43:05

转到 Jenkins 主页 → 管理 Jenkins → 脚本控制台

def jobName = "copy_folder"  
def job = Jenkins.instance.getItem(jobName)  
def maxBuildNumber = job.getBuilds().collect { it.number }.max() ?: 0
job.getBuilds().each { it.delete() }  
job.nextBuildNumber = maxBuildNumber + 1   
job.save()

Go to your Jenkins home page → Manage Jenkins → Script Console

def jobName = "copy_folder"  
def job = Jenkins.instance.getItem(jobName)  
def maxBuildNumber = job.getBuilds().collect { it.number }.max() ?: 0
job.getBuilds().each { it.delete() }  
job.nextBuildNumber = maxBuildNumber + 1   
job.save()

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