NSString 和 NSUrl 未正确转换
因此，我尝试从来自 URL 的 XML 流中检索数据。该 URL 是根据用户输入的搜索字符串配置的。这段代码有什么理由不能工作吗？
NSString *searchString = "Geoff";
NSString *updatedURL = [NSString stringWithFormat:@"http://mysearchpage.com/searchQuery=%@", searchString];
NSLog(updatedURL);
NSURL *url = [[NSURL alloc] initWithString:updatedURL];
现在，这对于单个单词搜索来说效果很好，但是一旦我尝试搜索名字和姓氏，URL 每次都会返回 nil。字符串是否有任何行为可能导致这种情况？
当附加搜索字符串时，我什至尝试用“%20”替换“”，看看这是否是问题所在。我这样做是用：
NSURL *url = [[NSURL alloc] initWithString:[updatedURL stringByReplacingOccurrencesOfString:@" " withString:@"%%20"]];
有什么想法吗？提前致谢！
So I am trying to retrieve data from an XML stream coming from a URL. This URL is configured on a search string the user inputs. Is there any reason why this code should not be working?
NSString *searchString = "Geoff";
NSString *updatedURL = [NSString stringWithFormat:@"http://mysearchpage.com/searchQuery=%@", searchString];
NSLog(updatedURL);
NSURL *url = [[NSURL alloc] initWithString:updatedURL];
Now this works fine for single word searches, but as soon as I try and search for like a first and last name, the URL returns nil every time. Is there any behavior with the strings that may be causing that?
I have even tried to replace the " "'s with "%20"'s when the search string was appended to see if that was the problem. I did that using:
NSURL *url = [[NSURL alloc] initWithString:[updatedURL stringByReplacingOccurrencesOfString:@" " withString:@"%%20"]];
any ideas? Thanks in advance!
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您应该使用 NSString 的
-stringByAddingPercentEscapesUsingEncoding:方法：You should use NSString's
-stringByAddingPercentEscapesUsingEncoding:method for that:如果这确实是副本&粘贴您的代码，可能是因为
searchString缺少@符号。这应该是NSString *searchString = @"Geoff";If this is indeed a copy & paste of your code, it might be because the
searchStringis missing the@-sign. This should beNSString *searchString = @"Geoff";