Perl 准备 DB2 语句没有返回我需要的内容

发布于 2024-09-12 22:26:42 字数 665 浏览 10 评论 0原文

由于我使用的是 DB2,为了选择中间数据库的一部分(如限制/偏移配对),我需要执行不同类型的准备语句。我得到的例子是这样的:

SELECT * FROM (SELECT col1, col2, col3, ROW_NUMBER() OVER () AS RN FROM 表) AS cols 其中 RN 介于 1 和 10000 之间;

我对此进行了调整:

SELECT * FROM (SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) AS foo WHERE rownum >= 500 AND rownum <1000

当我调用 fetchall_arrayref(),我确实得到了 500 个结果,就像我想要的那样,但它只返回一个包含行号引用的数组,而不是我想要提取的所有数据。我知道一个事实,那就是代码应该按照其编写的方式执行操作,并且我尝试了一系列排列来获得我想要的结果,但没有运气。

我想要的只是将所有列(如我之前的准备语句)抓取到数组数组中: SELECT * FROM TU_TRANSACTIONS ORDER BY 2, 3, 4, 6, 7

但仅在指定部分。我只是缺少一个基本的东西,而且我看不到它。

任何帮助都会受到赞赏,即使它伴随着一些建设性的批评。

Since I am using DB2, in order to select a portion of a database in the middle (like a limit/offset pairing), I need to do a different kind of prepare statement. The example I was given was this:

SELECT *
FROM (SELECT col1, col2, col3, ROW_NUMBER() OVER () AS RN FROM table) AS cols
WHERE RN BETWEEN 1 AND 10000;

Which I adapted to this:

SELECT * FROM (SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) AS foo WHERE rownum >= 500 AND rownum <1000

And when I call the fetchall_arrayref(), I do come out with 500 results like I want to, but it is only returning an array with references to the row number, and not all of the data I want to pull. I know for a fact that that is what the code is SUPPOSED to do as its written, and I have tried a bunch of permutations to get my desired result with no luck.

All I want is to grab all of the columns like my previous prepare statement into an array of arrays:
SELECT * FROM TU_TRANSACTIONS ORDER BY 2, 3, 4, 6, 7

but just on a designated section. There is just a fundamental thing I am missing, and I just cant see it.

Any help is appreciated, even if its paired with some constructive criticism.

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(2

花开雨落又逢春i 2024-09-19 22:26:42

您的表表达式:

(SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) as foo

只有一列 - rownum - 所以当您从“foo”中选择“*”时,您只获取一列。

您的表表达式需要包含您想要的所有列,就像您发布的示例一样。

Your table expression:

(SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) as foo

Has only one column - rownum - so when you select "*" from "foo" you get only the one column.

Your table expression needs to include all of the columns you want, just like e example you posted.

冷︶言冷语的世界 2024-09-19 22:26:42

我不使用 DB2,所以我可能会偏离基础,但似乎:

SELECT * FROM (SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) AS foo WHERE rownum >= 500 AND rownum <1000

只会返回行号,因为虽然子查询引用了表,但主查询却没有。看起来它会看到的只是一组数字(这将返回填充了数字的单列)

也许这会起作用:

SELECT * FROM TRANSACTIONS, (SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) AS foo WHERE rownum >= 500 AND rownum <1000

I don't use DB2 so I could be off-base but it seems that:

SELECT * FROM (SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) AS foo WHERE rownum >= 500 AND rownum <1000

Would only return the row numbers because while the sub-query references the table the main query does not. All it seems it would see is the set of numbers (which would return a single column with the number filled in)

Perhaps this would work:

SELECT * FROM TRANSACTIONS, (SELECT ROW_NUMBER() OVER (ORDER BY 2,3,4,6,7 ASC) AS rownum FROM TRANSACTIONS) AS foo WHERE rownum >= 500 AND rownum <1000
~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文