Powershell 1.0 中的异常处理
我正在使用以下代码使用 PowerShell 1.0 上传文件。如何判断上传是否成功完成或是否出现错误？如果上传成功，我需要删除该文件。
我尝试过的：
1.陷阱条款。似乎无法让这个工作。
2. 检查$webclient.UploadFile的返回值——无论成功与否，这似乎总是一个空字符串
$File = "D:\Dev\somefilename.zip"
$ftp = "ftp://username:[email protected]/pub/incoming/somefilename.zip"
“ftp url：$ftp”
$webclient = 新对象 System.Net.WebClient
$uri = New-Object System.Uri($ftp)
"正在上传$File..."
$webclient.UploadFile($uri, $File)
I am using the following code to upload a file using PowerShell 1.0. How can I tell if the upload completed successfully or if there was an error? I need to delete the file if the upload was successful.
What I have tried:
1. the trap clause. Cant seem to get this one to work.
2. Checking the return value of $webclient.UploadFile -- this seems to always be an empty string, success or not
$File = "D:\Dev\somefilename.zip" $ftp = "ftp://username:[email protected]/pub/incoming/somefilename.zip""ftp url: $ftp"
$webclient = New-Object System.Net.WebClient $uri = New-Object System.Uri($ftp)
"Uploading $File..."
$webclient.UploadFile($uri, $File)
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将陷阱放入新的范围中，以便捕获上传引发的异常，例如：
您还可以尝试捕获特定的异常，如下所示：
Drop the trap down into a new scope so that you trap on the exception thrown by Upload e.g.:
You could also try to catch a specific exception like so:
UploadFile方法是同步的。如果它完成且没有抛出异常，那么您就成功了。如果失败，您应该得到一个可捕获的 WebException。http://msdn.microsoft.com/en-us/library/36s52zhs。 aspx
我将省略有关错误捕获的详细信息，因为看来您已经熟悉它了。
The
UploadFilemethod is synchronous. If it completes without throwing an exception, you have had success. You should get a trappable WebException if it fails.http://msdn.microsoft.com/en-us/library/36s52zhs.aspx
I'll leave out details about error trapping, as it appears you are familiar with it already.