PHP 输出单词不在字符串中

Question

我有两个字符串：

$string = shell_exec('reg.bat '.$arg); //returns word\0word\0word
$stringA = "$string";
$stringB = "word,other,word2,other2";
$array1 = explode('\0', $stringA);
$array2 = explode(',', $stringB);
$result = array_diff($array1, $array2);

我可以使用 array_diff 来查找差异，但最后一个单词显示为不在两个字符串中，即使这是因为 \0 分隔符。

Answer 1

尝试：

$stringA = "word,other,word2,other";
$stringB = "word,other,word2,other2";

$array1 = explode(',', $stringA);
$array2 = explode(',', $stringB);

$result = array_diff($array2, $array1);

echo '<pre>';
print_r($result);

结果：

Array
(
    [3] => other2
)

更多信息：

• https://www.php.net/manual/en/function.array-diff.php

Answer 2

将字符串分解为数组并查看 array_diff 功能。

Answer 3

您可以使用 array_diff 和 str_word_count：

print_r(
    array_diff(
        str_word_count("word\0word\0word", 1, '0123456789'),
        str_word_count("word,other,word2,other2", 1, '0123456789'))
);
// will return an empty array, because "word" is in "word,other,word2,other2"

或者切换输入：

print_r(
    array_diff(
        str_word_count("word,other,word2,other2", 1, '0123456789'),
        str_word_count("word\0word\0word", 1, '0123456789'))
);
// will return an array containing "other", "word2", "other"