有没有一种简单的方法来为一组不相关的对象定义一个公共接口？

发布于 2024-09-12 14:34:48 字数 245 浏览 3 评论 0 原文

我有一个序列化数据的类。我可能想将此数据序列化为 JSON 或 YAML。在这种情况下，我可以干净地将 YAML 替换为 JSON 对象吗？我希望我能做如下的事情。这是一个白日梦吗？

FORMATS = {
  :json => JSON,
  :yaml => YAML,
}

def serialize(data, format)
  FORMATS[format].serialize(data)
end

原文

I've got a class that serializes data. I may want to serialize this data as JSON, or perhaps YAML. Can I cleanly swap YAML for JSON objects in this case? I was hoping I could do something like the following. Is it a pipe dream?

FORMATS = {
  :json => JSON,
  :yaml => YAML,
}

def serialize(data, format)
  FORMATS[format].serialize(data)
end

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满地尘埃落定 2024-09-19 14:34:48

如果类 JSON 和 YAML 都具有名为 serialize 的类方法，那么您编写的代码应该可以正常工作。但我认为实际存在的方法是#dump。

所以，你会：

require 'json'
require 'yaml'

FORMATS = {
  :json => JSON,
  :yaml => YAML,
}

def serialize(data, format)
  FORMATS[format].dump(data)
end

hash = {:a => 2}
puts serialize hash, :json
#=> {"a":2}

puts serialize hash, :yaml
#=> --- 
#=> :a: 2

The code you have written should work just fine, provided that classes JSON and YAML both have class method called serialize. But I think the method that actually exists is #dump.

So, you would have:

require 'json'
require 'yaml'

FORMATS = {
  :json => JSON,
  :yaml => YAML,
}

def serialize(data, format)
  FORMATS[format].dump(data)
end

hash = {:a => 2}
puts serialize hash, :json
#=> {"a":2}

puts serialize hash, :yaml
#=> --- 
#=> :a: 2

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风吹雪碎 2024-09-19 14:34:48

如果 JSON 和 YAML 是已经存在的类或模块，您可以编写：

FORMATS = { :json => "JSON", :yaml => "YAML" }

def serialize(data, format)
    Kernel.const_get(FORMATS[format]).serialize(data) # 'serialize' is a class method in this case
end

If JSON and YAML are classes or modules that already exist, you can write:

FORMATS = { :json => "JSON", :yaml => "YAML" }

def serialize(data, format)
    Kernel.const_get(FORMATS[format]).serialize(data) # 'serialize' is a class method in this case
end

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