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C++将字符串转换为十六进制，反之亦然

发布于 2024-09-12 07:26:35 字数 249 浏览 4 评论 0原文

在 C++ 中将字符串转换为十六进制或反之亦然的最佳方法是什么？

示例：

  • 将 "Hello World" 等字符串转换为十六进制格式：48656C6C6F20576F726C64
  • 并从十六进制 48656C6C6F20576F726C64 转换为字符串："Hello World"< /代码>
原文

What is the best way to convert a string to hex and vice versa in C++?

Example:

  • A string like "Hello World" to hex format: 48656C6C6F20576F726C64
  • And from hex 48656C6C6F20576F726C64 to string: "Hello World"

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评论（14）

久而酒知 2024-09-19 07:26:35

类似“Hello World”的十六进制格式字符串：48656C6C6F20576F726C64。

啊，给你：（

#include <string>

std::string string_to_hex(const std::string& input)
{
    static const char hex_digits[] = "0123456789ABCDEF";

    std::string output;
    output.reserve(input.length() * 2);
    for (unsigned char c : input)
    {
        output.push_back(hex_digits[c >> 4]);
        output.push_back(hex_digits[c & 15]);
    }
    return output;
}

#include <stdexcept>

int hex_value(unsigned char hex_digit)
{
    static const signed char hex_values[256] = {
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
         0,  1,  2,  3,  4,  5,  6,  7,  8,  9, -1, -1, -1, -1, -1, -1,
        -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
    };
    int value = hex_values[hex_digit];
    if (value == -1) throw std::invalid_argument("invalid hex digit");
    return value;
}

std::string hex_to_string(const std::string& input)
{
    const auto len = input.length();
    if (len & 1) throw std::invalid_argument("odd length");

    std::string output;
    output.reserve(len / 2);
    for (auto it = input.begin(); it != input.end(); )
    {
        int hi = hex_value(*it++);
        int lo = hex_value(*it++);
        output.push_back(hi << 4 | lo);
    }
    return output;
}

这里假设一个 char 有 8 位，所以它不是很便携，但你可以从这里获取它。）

A string like "Hello World" to hex format: 48656C6C6F20576F726C64.

Ah, here you go:

#include <string>

std::string string_to_hex(const std::string& input)
{
    static const char hex_digits[] = "0123456789ABCDEF";

    std::string output;
    output.reserve(input.length() * 2);
    for (unsigned char c : input)
    {
        output.push_back(hex_digits[c >> 4]);
        output.push_back(hex_digits[c & 15]);
    }
    return output;
}

#include <stdexcept>

int hex_value(unsigned char hex_digit)
{
    static const signed char hex_values[256] = {
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
         0,  1,  2,  3,  4,  5,  6,  7,  8,  9, -1, -1, -1, -1, -1, -1,
        -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, 10, 11, 12, 13, 14, 15, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
        -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,
    };
    int value = hex_values[hex_digit];
    if (value == -1) throw std::invalid_argument("invalid hex digit");
    return value;
}

std::string hex_to_string(const std::string& input)
{
    const auto len = input.length();
    if (len & 1) throw std::invalid_argument("odd length");

    std::string output;
    output.reserve(len / 2);
    for (auto it = input.begin(); it != input.end(); )
    {
        int hi = hex_value(*it++);
        int lo = hex_value(*it++);
        output.push_back(hi << 4 | lo);
    }
    return output;
}

(This assumes that a char has 8 bits, so it's not very portable, but you can take it from here.)

回复 原文
独留℉清风醉 2024-09-19 07:26:35
string ToHex(const string& s, bool upper_case /* = true */)
{
    ostringstream ret;

    for (string::size_type i = 0; i < s.length(); ++i)
        ret << std::hex << std::setfill('0') << std::setw(2) << (upper_case ? std::uppercase : std::nouppercase) << (int)s[i];

    return ret.str();
}

int FromHex(const string &s) { return strtoul(s.c_str(), NULL, 16); }

string ToHex(const string& s, bool upper_case /* = true */)
{
    ostringstream ret;

    for (string::size_type i = 0; i < s.length(); ++i)
        ret << std::hex << std::setfill('0') << std::setw(2) << (upper_case ? std::uppercase : std::nouppercase) << (int)s[i];

    return ret.str();
}

int FromHex(const string &s) { return strtoul(s.c_str(), NULL, 16); }
回复 原文
北城半夏 2024-09-19 07:26:35

使用查找表之类的方法是可行的，但有点矫枉过正，这里有一些非常简单的方法，可以将字符串转换为十六进制，然后将十六进制转换回字符串：

#include <stdexcept>
#include <sstream>
#include <iomanip>
#include <string>
#include <cstdint>

std::string string_to_hex(const std::string& in) {
    std::stringstream ss;

    ss << std::hex << std::setfill('0');
    for (size_t i = 0; in.length() > i; ++i) {
        ss << std::setw(2) << static_cast<unsigned int>(static_cast<unsigned char>(in[i]));
    }

    return ss.str(); 
}

std::string hex_to_string(const std::string& in) {
    std::string output;

    if ((in.length() % 2) != 0) {
        throw std::runtime_error("String is not valid length ...");
    }

    size_t cnt = in.length() / 2;

    for (size_t i = 0; cnt > i; ++i) {
        uint32_t s = 0;
        std::stringstream ss;
        ss << std::hex << in.substr(i * 2, 2);
        ss >> s;

        output.push_back(static_cast<unsigned char>(s));
    }

    return output;
}

Using lookup tables and the like works, but is just overkill, here are some very simple ways of taking a string to hex and hex back to a string:

#include <stdexcept>
#include <sstream>
#include <iomanip>
#include <string>
#include <cstdint>

std::string string_to_hex(const std::string& in) {
    std::stringstream ss;

    ss << std::hex << std::setfill('0');
    for (size_t i = 0; in.length() > i; ++i) {
        ss << std::setw(2) << static_cast<unsigned int>(static_cast<unsigned char>(in[i]));
    }

    return ss.str(); 
}

std::string hex_to_string(const std::string& in) {
    std::string output;

    if ((in.length() % 2) != 0) {
        throw std::runtime_error("String is not valid length ...");
    }

    size_t cnt = in.length() / 2;

    for (size_t i = 0; cnt > i; ++i) {
        uint32_t s = 0;
        std::stringstream ss;
        ss << std::hex << in.substr(i * 2, 2);
        ss >> s;

        output.push_back(static_cast<unsigned char>(s));
    }

    return output;
}
回复 原文
绮烟 2024-09-19 07:26:35

我认为有一个更简单、更优雅的解决方案。在某些情况下，上述一些方法甚至可能会抛出未处理的异常。这是一个万无一失（永远不会出错）且非常快的代码。只需尝试一下，并比较速度和紧凑性方面的结果：

#include <string>

// Convert string of chars to its representative string of hex numbers
void stream2hex(const std::string str, std::string& hexstr, bool capital = false)
{
    hexstr.resize(str.size() * 2);
    const size_t a = capital ? 'A' - 1 : 'a' - 1;

    for (size_t i = 0, c = str[0] & 0xFF; i < hexstr.size(); c = str[i / 2] & 0xFF)
    {
        hexstr[i++] = c > 0x9F ? (c / 16 - 9) | a : c / 16 | '0';
        hexstr[i++] = (c & 0xF) > 9 ? (c % 16 - 9) | a : c % 16 | '0';
    }
}

// Convert string of hex numbers to its equivalent char-stream
void hex2stream(const std::string hexstr, std::string& str)
{
    str.resize((hexstr.size() + 1) / 2);

    for (size_t i = 0, j = 0; i < str.size(); i++, j++)
    {
        str[i] = (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) << 4, j++;
        str[i] |= (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) & 0xF;
    }
}

测试代码：

#include <iostream>
int main()
{
    std::string s = "Hello World!";
    std::cout << "original string: " << s << '\n';
    stream2hex(s, s);
    std::cout << "hex format: " << s << '\n';
    hex2stream(s, s);
    std::cout << "original one: " << s << '\n';
}

和结果是：

original string: Hello World!
hex format: 48656C6C6F20576F726C6421
original one: Hello World!

I think there is a much simpler and more elegant solution. Some of the above-mentioned methods may even throw unhandled exceptions in some cases. Here is a fool-proof (as in never goes wrong) and very fast code. Just try it and compare the results in terms of speed and compactness:

#include <string>

// Convert string of chars to its representative string of hex numbers
void stream2hex(const std::string str, std::string& hexstr, bool capital = false)
{
    hexstr.resize(str.size() * 2);
    const size_t a = capital ? 'A' - 1 : 'a' - 1;

    for (size_t i = 0, c = str[0] & 0xFF; i < hexstr.size(); c = str[i / 2] & 0xFF)
    {
        hexstr[i++] = c > 0x9F ? (c / 16 - 9) | a : c / 16 | '0';
        hexstr[i++] = (c & 0xF) > 9 ? (c % 16 - 9) | a : c % 16 | '0';
    }
}

// Convert string of hex numbers to its equivalent char-stream
void hex2stream(const std::string hexstr, std::string& str)
{
    str.resize((hexstr.size() + 1) / 2);

    for (size_t i = 0, j = 0; i < str.size(); i++, j++)
    {
        str[i] = (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) << 4, j++;
        str[i] |= (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) & 0xF;
    }
}

Test the code:

#include <iostream>
int main()
{
    std::string s = "Hello World!";
    std::cout << "original string: " << s << '\n';
    stream2hex(s, s);
    std::cout << "hex format: " << s << '\n';
    hex2stream(s, s);
    std::cout << "original one: " << s << '\n';
}

and the result is:

original string: Hello World!
hex format: 48656C6C6F20576F726C6421
original one: Hello World!
回复 原文
葵雨 2024-09-19 07:26:35

从 C++17 开始，还有 std::from_chars。以下函数接受十六进制字符的字符串并返回 T 的向量：

#include <charconv>

template<typename T>
std::vector<T> hexstr_to_vec(const std::string& str, unsigned char chars_per_num = 2)
{
  std::vector<T> out(str.size() / chars_per_num, 0);

  T value;
  for (std::size_t i = 0; i < str.size() / chars_per_num; i++) {
    std::from_chars<T>(
      str.data() + (i * chars_per_num),
      str.data() + (i * chars_per_num) + chars_per_num,
      value,
      16
    );
    out[i] = value;
  }

  return out;
}

As of C++17 there's also std::from_chars. The following function takes a string of hex characters and returns a vector of T:

#include <charconv>

template<typename T>
std::vector<T> hexstr_to_vec(const std::string& str, unsigned char chars_per_num = 2)
{
  std::vector<T> out(str.size() / chars_per_num, 0);

  T value;
  for (std::size_t i = 0; i < str.size() / chars_per_num; i++) {
    std::from_chars<T>(
      str.data() + (i * chars_per_num),
      str.data() + (i * chars_per_num) + chars_per_num,
      value,
      16
    );
    out[i] = value;
  }

  return out;
}
回复 原文
巴黎盛开的樱花 2024-09-19 07:26:35

你可以试试这个。它正在工作...

#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>

namespace {
   const std::string test="hello world";
}

int main() {
   std::ostringstream result;
   result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
   std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
   std::cout << test << ":" << result.str() << std::endl;
}

You can try this. It's Working...

#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>

namespace {
   const std::string test="hello world";
}

int main() {
   std::ostringstream result;
   result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
   std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
   std::cout << test << ":" << result.str() << std::endl;
}
回复 原文
闻呓 2024-09-19 07:26:35

使用标准库的最简单示例。

#include <iostream>
using namespace std;

int main()
{
  char c = 'n';
  cout << "HEX " << hex << (int)c << endl;  // output in hexadecimal
  cout << "ASC" << c << endl; // output in ascii
  return 0;
}

要检查输出，codepad 返回：6e

和在线 ascii 到十六进制转换工具 也产生 6e。所以它有效。

您还可以这样做：

template<class T> std::string toHexString(const T& value, int width) {
    std::ostringstream oss;
    oss << hex;
    if (width > 0) {
        oss << setw(width) << setfill('0');
    }
    oss << value;
    return oss.str();
}

Simplest example using the Standard Library.

#include <iostream>
using namespace std;

int main()
{
  char c = 'n';
  cout << "HEX " << hex << (int)c << endl;  // output in hexadecimal
  cout << "ASC" << c << endl; // output in ascii
  return 0;
}

To check the output, codepad returns: 6e

and an online ascii-to-hexadecimal conversion tool yields 6e as well. So it works.

You can also do this:

template<class T> std::string toHexString(const T& value, int width) {
    std::ostringstream oss;
    oss << hex;
    if (width > 0) {
        oss << setw(width) << setfill('0');
    }
    oss << value;
    return oss.str();
}
回复 原文
弄潮 2024-09-19 07:26:35

这有点快：

static const char* s_hexTable[256] = 
{
    "00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0a", "0b", "0c", "0d", "0e", "0f", "10", "11",
    "12", "13", "14", "15", "16", "17", "18", "19", "1a", "1b", "1c", "1d", "1e", "1f", "20", "21", "22", "23",
    "24", "25", "26", "27", "28", "29", "2a", "2b", "2c", "2d", "2e", "2f", "30", "31", "32", "33", "34", "35",
    "36", "37", "38", "39", "3a", "3b", "3c", "3d", "3e", "3f", "40", "41", "42", "43", "44", "45", "46", "47",
    "48", "49", "4a", "4b", "4c", "4d", "4e", "4f", "50", "51", "52", "53", "54", "55", "56", "57", "58", "59",
    "5a", "5b", "5c", "5d", "5e", "5f", "60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6a", "6b",
    "6c", "6d", "6e", "6f", "70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7a", "7b", "7c", "7d",
    "7e", "7f", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8a", "8b", "8c", "8d", "8e", "8f",
    "90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9a", "9b", "9c", "9d", "9e", "9f", "a0", "a1",
    "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "aa", "ab", "ac", "ad", "ae", "af", "b0", "b1", "b2", "b3",
    "b4", "b5", "b6", "b7", "b8", "b9", "ba", "bb", "bc", "bd", "be", "bf", "c0", "c1", "c2", "c3", "c4", "c5",
    "c6", "c7", "c8", "c9", "ca", "cb", "cc", "cd", "ce", "cf", "d0", "d1", "d2", "d3", "d4", "d5", "d6", "d7",
    "d8", "d9", "da", "db", "dc", "dd", "de", "df", "e0", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "e9",
    "ea", "eb", "ec", "ed", "ee", "ef", "f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "fa", "fb",
    "fc", "fd", "fe", "ff"
};

// Convert binary data sequence [beginIt, endIt) to hexadecimal string
void dataToHexString(const uint8_t*const beginIt, const uint8_t*const endIt, string& str)
{
    str.clear();
    str.reserve((endIt - beginIt) * 2);
    for(const uint8_t* it(beginIt); it != endIt; ++it)
    {
        str += s_hexTable[*it];
    }
}

This is a bit faster:

static const char* s_hexTable[256] = 
{
    "00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0a", "0b", "0c", "0d", "0e", "0f", "10", "11",
    "12", "13", "14", "15", "16", "17", "18", "19", "1a", "1b", "1c", "1d", "1e", "1f", "20", "21", "22", "23",
    "24", "25", "26", "27", "28", "29", "2a", "2b", "2c", "2d", "2e", "2f", "30", "31", "32", "33", "34", "35",
    "36", "37", "38", "39", "3a", "3b", "3c", "3d", "3e", "3f", "40", "41", "42", "43", "44", "45", "46", "47",
    "48", "49", "4a", "4b", "4c", "4d", "4e", "4f", "50", "51", "52", "53", "54", "55", "56", "57", "58", "59",
    "5a", "5b", "5c", "5d", "5e", "5f", "60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6a", "6b",
    "6c", "6d", "6e", "6f", "70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7a", "7b", "7c", "7d",
    "7e", "7f", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8a", "8b", "8c", "8d", "8e", "8f",
    "90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9a", "9b", "9c", "9d", "9e", "9f", "a0", "a1",
    "a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "aa", "ab", "ac", "ad", "ae", "af", "b0", "b1", "b2", "b3",
    "b4", "b5", "b6", "b7", "b8", "b9", "ba", "bb", "bc", "bd", "be", "bf", "c0", "c1", "c2", "c3", "c4", "c5",
    "c6", "c7", "c8", "c9", "ca", "cb", "cc", "cd", "ce", "cf", "d0", "d1", "d2", "d3", "d4", "d5", "d6", "d7",
    "d8", "d9", "da", "db", "dc", "dd", "de", "df", "e0", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "e9",
    "ea", "eb", "ec", "ed", "ee", "ef", "f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "fa", "fb",
    "fc", "fd", "fe", "ff"
};

// Convert binary data sequence [beginIt, endIt) to hexadecimal string
void dataToHexString(const uint8_t*const beginIt, const uint8_t*const endIt, string& str)
{
    str.clear();
    str.reserve((endIt - beginIt) * 2);
    for(const uint8_t* it(beginIt); it != endIt; ++it)
    {
        str += s_hexTable[*it];
    }
}
回复 原文
原来分手还会想你 2024-09-19 07:26:35

这会将 Hello World 转换为 48656c6c6f20576f726c64 并打印它。

#include <iostream>
#include <cstring>

using namespace std;

int main()
{
    char hello[20]="Hello World";

    for(unsigned int i=0; i<strlen(hello); i++)
        cout << hex << (int) hello[i];
    return 0;
}

This will convert Hello World to 48656c6c6f20576f726c64 and print it.

#include <iostream>
#include <cstring>

using namespace std;

int main()
{
    char hello[20]="Hello World";

    for(unsigned int i=0; i<strlen(hello); i++)
        cout << hex << (int) hello[i];
    return 0;
}
回复 原文
倚栏听风 2024-09-19 07:26:35

这是另一种解决方案，很大程度上受到@fredoverflow 的解决方案的启发。

/**
 * Return hexadecimal representation of the input binary sequence
 */
std::string hexitize(const std::vector<char>& input, const char* const digits = "0123456789ABCDEF")
{
    std::ostringstream output;

    for (unsigned char gap = 0, beg = input[gap]; gap < input.length(); beg = input[++gap])
        output << digits[beg >> 4] << digits[beg & 15];

    return output.str();
}

长度是预期用途中必需的参数。

Here is an other solution, largely inspired by the one by @fredoverflow.

/**
 * Return hexadecimal representation of the input binary sequence
 */
std::string hexitize(const std::vector<char>& input, const char* const digits = "0123456789ABCDEF")
{
    std::ostringstream output;

    for (unsigned char gap = 0, beg = input[gap]; gap < input.length(); beg = input[++gap])
        output << digits[beg >> 4] << digits[beg & 15];

    return output.str();
}

Length was required parameter in the intended usage.

回复 原文
心如荒岛 2024-09-19 07:26:35

这会将“Hello World”转换为“48656c6c6f20576f726c64”，并将该十六进制值存储在 str1 中，并将“48656c6c6f20576f726c64”转换为“Hello World”。

#include <iostream>
#include<sstream>

using namespace std;
int hexCharToInt(char);
string hexToString(string);
int main()
{
    std::string str;
    std::stringstream str1;

    str="Hello World";
    for(int i=0;i<str.length();i++){
        str1 << std::hex << (int)str.at(i);
    }
    std::cout << str1.str() <<"\n";
    string test = "48656c6c6f20576f726c64";
    std::cout << hexToString(test) <<"\n";
    return 0;
}
string hexToString(string str){
    std::stringstream HexString;
    for(int i=0;i<str.length();i++){
        char a = str.at(i++);
        char b = str.at(i);
        int x = hexCharToInt(a);
        int y = hexCharToInt(b);
        HexString << (char)((16*x)+y);
    }
    return HexString.str();
}

int hexCharToInt(char a){
    if(a>='0' && a<='9')
        return(a-48);
    else if(a>='A' && a<='Z')
        return(a-55);
    else
        return(a-87);
}

This will convert "Hello World" to "48656c6c6f20576f726c64" and will store this hex value in str1 and also will convert "48656c6c6f20576f726c64" to "Hello World".

#include <iostream>
#include<sstream>

using namespace std;
int hexCharToInt(char);
string hexToString(string);
int main()
{
    std::string str;
    std::stringstream str1;

    str="Hello World";
    for(int i=0;i<str.length();i++){
        str1 << std::hex << (int)str.at(i);
    }
    std::cout << str1.str() <<"\n";
    string test = "48656c6c6f20576f726c64";
    std::cout << hexToString(test) <<"\n";
    return 0;
}
string hexToString(string str){
    std::stringstream HexString;
    for(int i=0;i<str.length();i++){
        char a = str.at(i++);
        char b = str.at(i);
        int x = hexCharToInt(a);
        int y = hexCharToInt(b);
        HexString << (char)((16*x)+y);
    }
    return HexString.str();
}

int hexCharToInt(char a){
    if(a>='0' && a<='9')
        return(a-48);
    else if(a>='A' && a<='Z')
        return(a-55);
    else
        return(a-87);
}
回复 原文
比忠 2024-09-19 07:26:35
#include "boost/algorithm/hex.hpp"
std::string hexed = boost::algorithm::hex(std::string("input"));

https://www.boost.org/doc/libs/ 1_78_0/boost/algorithm/hex.hpp

#include "boost/algorithm/hex.hpp"
std::string hexed = boost::algorithm::hex(std::string("input"));

https://www.boost.org/doc/libs/1_78_0/boost/algorithm/hex.hpp

回复 原文
紙鸢 2024-09-19 07:26:35

这适用于打印 UTF-8 编码的字符串（长度可变）

// std::string
void printHex1(const std::string & str)
{
  printf("%s 1: ", str.c_str());
  for (size_t i = 0; i < str.size(); i++)
    printf("%X ", str[i]);
  printf("\n");
}

// c-style string
void printHex2(const char * buf)
{
  printf("%s 2: ", buf);
  size_t i = 0;
  while (buf[i] != 0) {
    printf("%X ", buf[i]);
    i++;
  }
  printf("\n");
}

小测试

std::string test_vector = "Cigueña";
char c_vector[128];
strncpy(c_vector, test_vector.c_str(), 128);
printHex1(test_vector);
printHex2(c_vector);

输出：

Cigueña 1: 43 69 67 75 65 FFFFFFC3 FFFFFFB1 61 
Cigueña 2: 43 69 67 75 65 FFFFFFC3 FFFFFFB1 61

查看如何 UTF-8 字符 ñ 使用更多字节进行编码。

This works for printing UTF-8 encoded strings (which are variable in length)

// std::string
void printHex1(const std::string & str)
{
  printf("%s 1: ", str.c_str());
  for (size_t i = 0; i < str.size(); i++)
    printf("%X ", str[i]);
  printf("\n");
}

// c-style string
void printHex2(const char * buf)
{
  printf("%s 2: ", buf);
  size_t i = 0;
  while (buf[i] != 0) {
    printf("%X ", buf[i]);
    i++;
  }
  printf("\n");
}

Little test

std::string test_vector = "Cigueña";
char c_vector[128];
strncpy(c_vector, test_vector.c_str(), 128);
printHex1(test_vector);
printHex2(c_vector);

The output:

Cigueña 1: 43 69 67 75 65 FFFFFFC3 FFFFFFB1 61 
Cigueña 2: 43 69 67 75 65 FFFFFFC3 FFFFFFB1 61

See how UTF-8 characters ñ are encoded using more bytes.

回复 原文
游魂 2024-09-19 07:26:35

为什么没有人使用 sprintf？

#include <string>
#include <stdio.h>

static const std::string str = "hello world!";

int main()
{
  //copy the data from the string to a char array
  char *strarr = new char[str.size()+1];
  strarr[str.size()+1] = 0; //set the null terminator
  memcpy(strarr, str.c_str(),str.size()); //memory copy to the char array

  printf(strarr);
  printf("\n\nHEX: ");

  //now print the data
  for(int i = 0; i < str.size()+1; i++)
  {
    char x = strarr[i];
    sprintf("%x ", reinterpret_cast<const char*>(x));
  }

  //DO NOT FORGET TO DELETE
  delete(strarr);

  return 0;
}

Why has nobody used sprintf?

#include <string>
#include <stdio.h>

static const std::string str = "hello world!";

int main()
{
  //copy the data from the string to a char array
  char *strarr = new char[str.size()+1];
  strarr[str.size()+1] = 0; //set the null terminator
  memcpy(strarr, str.c_str(),str.size()); //memory copy to the char array

  printf(strarr);
  printf("\n\nHEX: ");

  //now print the data
  for(int i = 0; i < str.size()+1; i++)
  {
    char x = strarr[i];
    sprintf("%x ", reinterpret_cast<const char*>(x));
  }

  //DO NOT FORGET TO DELETE
  delete(strarr);

  return 0;
}
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