将 PinField.getPassword() 的输出转换为字符串
if ("Submit".equals(cmd)) { //Process the password.
String UserNameInput=UserName.getText();
///////////////////////////////ERROR Pin when printed shows error/////////////////////////////
char[] PinInput = PinField.getPassword();
String pinInput=PinInput.toString();
//for debugging , print PinInput , but it prints garbage
System.out.println("Pin entered is "+PinInput);
//pinInput has garabage instead of the Pin that was entered
//so the function isPasswordCorrect fails to verify UserName & Pin
if (isPasswordCorrect(UserNameInput,pinInput))
{
//some tasks
}
}
boolean isPasswordCorrect(String Username,String Pin)
{
//verify username & pin
}
我需要将 PinInput 从字符数组转换为字符串，以便我可以使用函数 isPasswordCorrect() 。当我使用 toString() 方法时，它会产生垃圾值，我应该做什么来转换 PinInput 的值到 String ？
if ("Submit".equals(cmd)) { //Process the password.
String UserNameInput=UserName.getText();
///////////////////////////////ERROR Pin when printed shows error/////////////////////////////
char[] PinInput = PinField.getPassword();
String pinInput=PinInput.toString();
//for debugging , print PinInput , but it prints garbage
System.out.println("Pin entered is "+PinInput);
//pinInput has garabage instead of the Pin that was entered
//so the function isPasswordCorrect fails to verify UserName & Pin
if (isPasswordCorrect(UserNameInput,pinInput))
{
//some tasks
}
}
boolean isPasswordCorrect(String Username,String Pin)
{
//verify username & pin
}
I need to convert the PinInput from character array to String, so that I can use the function isPasswordCorrect() . When I use toString() method , it produces garbage value , what should I do to convert
the value of PinInput to String ?
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查看 String API，有一个接受 char 数组的构造函数。
Look at the String API, there is a constructor that accepts a char array.
@camickr 是对的。那不是垃圾；那是垃圾。
pinField.getPassword().toString()显示char[]的地址，例如[C@fd54d6。附录：
String.valueOf(array)或new String(array)将转换getPassword()到String，但这会妨碍返回char[]的安全优势。考虑将值保留在本地并遵循 API 指南：“建议在使用后通过将每个字符设置为零来清除返回的字符数组。”@camickr is right. That's not garbage;
pinField.getPassword().toString()shows the address of thechar[], e.g.[C@fd54d6.Addendum:
String.valueOf(array)ornew String(array)will convert the result ofgetPassword()to aString, but this thwarts the security benefit of returning achar[]. Consider keeping the value local and following the API guidelines: "it is recommended that the returned character array be cleared after use by setting each character to zero."