无法解析 java.lang.NumberFormat 异常

Question

try{    
    if (flag_conv == false)
    {
      if ((Integer.parseInt(et1.getText().toString()))<=55)
      {
       final AlertDialog alertDialog = new AlertDialog.Builder(this).create();
       alertDialog.setTitle("Reset...");
       alertDialog.setMessage("WB should be grater than 55");

       alertDialog.setButton2("OK", new DialogInterface.OnClickListener() {
          public void onClick(DialogInterface dialog, int which) 
          {
                // here you can add functions
                dialog.dismiss();
          }});
       alertDialog.setIcon(R.drawable.icon);
       alertDialog.show();
       tv1.setText("WB");
       et1.setText("");
       wbflg = true;
       wbval = 0;
       return;          
     }
     else
     {                     
      wbval = Integer.parseInt(et1.getText().toString());
     }
   }
 catch(NumberFormatException nfe)
{System.out.println("Could not parse " + nfe);}

我得到了以下异常

07-31 14:48:45.409: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:50.569: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:54.599: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:54.829: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:54.958: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:55.108: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:55.259: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:48:55.409: DEBUG/dalvikvm(118): GREF has increased to 201
07-31 14:48:55.429: INFO/System.out(431): Could not parse java.lang.NumberFormatException: unable to parse '' as integer
07-31 14:52:43.798: DEBUG/SntpClient(58): request time failed: java.net.SocketException: Address family not supported by protocol

Answer 1

在 Integer.parseInt 上，

异常消息似乎如下：

07-31 14:48:45.409: INFO/System.out(431): Could not parse
   java.lang.NumberFormatException: unable to parse '' as integer

事实上，空字符串不能被 Integer.parseInt(String)。因此：

int num = Integer.parseInt("");
// throws java.lang.NumberFormatException: For input string: ""

如果您有一个任意的 String ，它可以是 isEmpty() 甚至 null，那么你必须有特殊的代码来处理它，因为Integer.parseInt(s) 将始终抛出异常。

当然 Integer.parseInt(s) 可以抛出 NumberFormatException 当 s 是例如 "xyz" 时，因此您可能需要将该语句放在 try-catch 块。

因此，您可以编写如下内容：

String s = ...;
if (s == null || s.isEmpty()) {
   complaintAboutNotGettingAnything();
} else {
   try {
     int num = Integer.parseInt(s);
     doSomethingWith(num);
   catch (NumberFormatException e) {
     complaintAboutGettingSomethingYouDontWant();
   }
}

---

关于编写易于调试的代码

在这个特定的代码片段中，parseInt 的调用方式如下：

if ((Integer.parseInt(et1.getText().toString()))<=55) ...

在这个表达式中，很多事情都可能出错。我建议重构，将其分解为逻辑可观察的步骤，如下所示：

String et1text = et1.getText().toString();
// maybe check if it's empty/null if necessary
// maybe log/inspect what the value of et1text is for debugging

try {
   int et1val = Integer.parseInt(et1text);
   if (et1val <= THRESHOLD) {
      // ...
   }
} catch (NumberFormatException e) {
   moreComplaining();
}

Answer 2

我不确定 Java，但如果你有可能不是有效整数的字符串
你可能有一个类似于 C# 中的函数：

bool res = Int.TryParse(s,ref int);