UIImagePickerController iPad 问题
我有以下代码：
UIImagePickerController *imagePicker = [[UIImagePickerController alloc] initWithRootViewController:self];
imagePicker.delegate = self;
popover = [[UIPopoverController alloc] initWithContentViewController:imagePicker];
[imagePicker release];
[popover presentPopoverFromRect:CGRectMake(100, 100.0, 0.0, 0.0)
inView:self.view
permittedArrowDirections:UIPopoverArrowDirectionAny
animated:YES];
但这只会破坏 self.view 并且根本不显示任何内容。当我将 inView: 设置为 [self.view window] 时，选择器至少会显示出来。但它仍然删除了 self.view。我必须做什么才能使视图不会消失？
I have the following code:
UIImagePickerController *imagePicker = [[UIImagePickerController alloc] initWithRootViewController:self];
imagePicker.delegate = self;
popover = [[UIPopoverController alloc] initWithContentViewController:imagePicker];
[imagePicker release];
[popover presentPopoverFromRect:CGRectMake(100, 100.0, 0.0, 0.0)
inView:self.view
permittedArrowDirections:UIPopoverArrowDirectionAny
animated:YES];
But this only destroys the self.view and does not show anything at all. When I set the inView: to [self.view window] the picker at least shows up. But it still removes the self.view. What do I have to do that the view doesn't disappear?
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评论（2）
您初始化 UIImagePickerController 错误。尝试将其更改为
You are initializing the UIImagePickerController wrong. Try changing it to
您正在尝试使用该视图本身在视图内显示弹出窗口！
initWithRootViewController 是要在弹出窗口中显示的视图（控制器）。
inview 是弹出窗口的视图
You are trying to show a popup inside a view with that view itself!
initWithRootViewController is the view(controller) to show inside the popup.
inview is the view where the popup will pop up