匹配所有不是数字后跟字母的内容
如果这个问题在其他地方得到了回答，我深表歉意——我做了一些搜索，但找不到答案。
假设我有一个包含一堆内容的文本文件。该内容中有一个职业代码，其格式始终为数字后跟大写字母。
如何从文件中仅提取 occ 代码？用简单的英语来说，我想删除文件中与数字大写字母模式不匹配的所有内容。
Apologies if this was answered elsewhere -- I did some searching and couldn't find the answer.
Suppose I have a text file that contains a bunch of content. In that content is an occupation code, which is always in the format of a number followed by a capital letter.
How can I extract ONLY the occ codes from the file? In plain english, I want to remove everything in the file that does not match the number-capital_letter pattern.
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您可以使用
/(\d+[AZ])/进行匹配You could match using
/(\d+[A-Z])/编写一个脚本，根据 occ 代码在文件中的显示方式逐行或逐字扫描，并可能使用 REGEX 检查匹配项，然后将它们写入另一个文件，这是一个简单的解决方案。
您可以在整个文档上使用单个正则表达式匹配并迭代结果，但这可能会引起问题，具体取决于文件的大小。
Writing a script that scans through line by line or word by word depending on the how the occ codes appear in the file and checking for matches possibly using a REGEX then wrting them to another file is a simple solution.
You COULD use a single regex match on the entire document and iterate over the results but that could pose problems depending on the size of the file.
这是使用 sed 删除除所需代码之外的所有内容的粗略尝试。 （请注意，我将“数字”解释为由一个或多个数字组成的字符串，没有小数点或前导减号。）
第一个命令删除大写字母后面不是数字的任何内容（因此可能是另一个数字的开头）代码），第二个删除后面跟着大写字母以外的任何数字，第三个删除尾随数字，第四个删除空白行。
我已经进行了一些测试，这似乎工作得很好。如果有人能找到失败的案例，我会很乐意修改它。
Here's a crude attempt to remove everything except the desired codes using sed. (Note that I interpret "number" to mean a string of one or more digits, no decimal point or leading minus sign.)
The first command removes anything after a capital letter that isn't a number (and therefore perhaps the beginning of another code), the second removes any number followed by something other than a capital letter, the third removes trailing numbers and the fourth removes blank lines.
I've run some tests and this seems to work pretty well. I'll happily amend it if anyone can find a case where it fails.