jQuery AJAX 无法按省份更新城市
正如标题所暗示的，我一直在使用 jQuery AJAX 尝试在选择省份时从数据库中提取城市列表。
我正在使用以下代码：
$('#province').change(function()
{
var province = $(this).val();
/*$.get("<?php echo site_url('cottage/cities'); ?>?province="+province, function(data)
{
console.log(data);
for (i=0;i<=data.length;i++)
{
//$('#citydiv').append(data['city']+'<br/>');
//$('#city').append('<option value="'+data[i]['city']+'">'+data[i]['city']+'</option>');
}
}); */
$.ajax({
url: "<?php echo site_url('cottage/cities'); ?>?province="+province,
method: 'GET',
dataType: 'json',
success: onDataReceived
});
function onDataReceived(series)
{
console.log(series);
}
});
而且我还有一个与之关联的省份和城市下拉菜单。 问题是我不断返回“未定义”，因为它不喜欢我的数据发送方式。
数据如下：
[{"city_id":"1107","city":"Young's Point","province":"Ontario","lat":"44.490345","lon":"-78.236008"},{"city_id":"1108","city":"Zurich","province":"Ontario","lat":"43.421185","lon":"-81.624832"}]
任何帮助将不胜感激！
As the title may suggest, I have been using jQuery AJAX to try and pull a list of Cities from a database when a Province is selected.
I am using the following code:
$('#province').change(function()
{
var province = $(this).val();
/*$.get("<?php echo site_url('cottage/cities'); ?>?province="+province, function(data)
{
console.log(data);
for (i=0;i<=data.length;i++)
{
//$('#citydiv').append(data['city']+'<br/>');
//$('#city').append('<option value="'+data[i]['city']+'">'+data[i]['city']+'</option>');
}
}); */
$.ajax({
url: "<?php echo site_url('cottage/cities'); ?>?province="+province,
method: 'GET',
dataType: 'json',
success: onDataReceived
});
function onDataReceived(series)
{
console.log(series);
}
});
And I also have a Province and City drop down associated with them.
The problem is that I keep getting "undefined" returned, as it doesn't like the way my data is sent.
The data looks like:
[{"city_id":"1107","city":"Young's Point","province":"Ontario","lat":"44.490345","lon":"-78.236008"},{"city_id":"1108","city":"Zurich","province":"Ontario","lat":"43.421185","lon":"-81.624832"}]
Any help would be greatly appreciated!
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评论（3）
json 编码的字符串看起来像这样
，而你有方括号
尝试使用 json_encode($array) 在 php 中对数据进行编码;
json encoded strings look like this
whereas you have square brackets
try encoding your data in php with json_encode($array);
你的数据应该看起来像
不要在数字周围加引号，使用括号等。
json_encode很有用（正如Christian Smorra所说）。Your data should look like
Don't put quotes around numbers, use brackets etc.
json_encodeis useful (as Christian Smorra stated).尝试使用 www.php.net/json_encode 正确编码您的 json 响应
在您的 onDataReceived() 函数中也对此进行检查以确保它是有效数据。
即使像这样简单的事情也可以阻止任何 JS 错误的发生。
Try properly encoding your json response with www.php.net/json_encode
In your onDataReceived() function perform a check on this also to make sure it's valid data.
Even something simple like this would to to stop any JS errors from occuring.