Javascript parseInt 给出了非常意想不到的结果
我正在解析一个字符串以检查它是否是一个日期，现在我们偶然发现我的方法不适用于八月或九月的日期。这就是我所做的（显然，输入并不是真正硬编码的，但为了简洁......）：
var str = '2010-08-26 14:53';
var data = str.split(' '); // ['2010-08-26', '14:53']
var date = data[0].split('-'); // ['2010', '08', '26]
var time = data[1].split(':'); // ['14', '53']
var yyyy = parseInt(date[0]); // 2010
// THIS IS WHERE STRANGE THINGS HAPPEN:
var MM = parseInt(date[1]); // 0 - not 08 or 8, as expected!
console.log(date[1]); // prints "08" (with quotes)
console.log(date[1].toString()); // prints 08 (no quotes)
console.log(parseInt(date[1].toString())); // prints 0 (!)
这个问题在八月和九月以及每个月的 8 号和 9 号出现 -也就是说，当 "08" 或 "09" 被解析为整数时，返回 0 而不是 8或<代码>9。该代码适用于较低的（例如 "07"）和较高的（例如 "10"）整数（至少在预期的日期范围内......）
我在做什么错误的？
Possible Duplicate:
Workarounds for JavaScript parseInt octal bug
I'm parsing a string to check if it's a date, and by chance we now discovered that my method doesn't work for dates in august or september. This is what I do (the input isn't really hard-coded, obviously, but for brevity...):
var str = '2010-08-26 14:53';
var data = str.split(' '); // ['2010-08-26', '14:53']
var date = data[0].split('-'); // ['2010', '08', '26]
var time = data[1].split(':'); // ['14', '53']
var yyyy = parseInt(date[0]); // 2010
// THIS IS WHERE STRANGE THINGS HAPPEN:
var MM = parseInt(date[1]); // 0 - not 08 or 8, as expected!
console.log(date[1]); // prints "08" (with quotes)
console.log(date[1].toString()); // prints 08 (no quotes)
console.log(parseInt(date[1].toString())); // prints 0 (!)
This problem arises for august and september, and for the 8th and 9th every month - that is, when either "08" or "09" is being parsed to integer, 0 is returned instead of 8 or 9. The code works for both lower (e.g. "07") and higher (e.g. "10") integers (at least within expected date ranges...)
What am I doing wrong?
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用于
确保字符串被解释为以 10 为基数（十进制）。
否则，如果以
"0"开头，则解释为基数 8（八进制）；如果以"0x"开头，则解释为基数 16（十六进制）。事实上，您应该始终包含基本参数以避免此类错误。
Use
to make sure the string is interpreted as base 10 (decimal).
Otherwise, it is interpreted as base 8 (octal) if it starts with
"0", or as base 16 (hexadecimal) if it starts with"0x".In fact, you should always include the base argument to avoid these kinds of bugs.
这是因为以 0 开头的数字被视为八进制数字，而“08”不是八进制，因此返回 0。
阅读此内容：http://mir.aculo。 us/2010/05/12/adventures-in-javascript-number-parsing/
That's because numbers that start with 0 are treated as octal numbers and "08" is not an octal so 0 is returned.
Read this: http://mir.aculo.us/2010/05/12/adventures-in-javascript-number-parsing/
parseInt() 函数有第二个可选基数参数。如果省略 radix 参数，JavaScript 会进行以下假设：
因此在您的情况下，它假定为八进制数。更改为 var MM = parseInt(date[1], 10); 就可以了
The parseInt() function has the second optional radix parameter. If the radix parameter is omitted, JavaScript assumes the following:
So in your case it assumes the octal numbers. Change to
var MM = parseInt(date[1], 10);and it will work听起来你的日期被解析为十六进制 - 前导零正在执行此操作。
因为 0-7 的十六进制和十进制表示形式是相同的，所以它“有效”，但 8 和 9 的转换不正确。
使用
显式指定基数。
It sounds like your date is being parsed as hex - the leading zero is doing this.
Because the hex and decimal representations are the same for 0-7 it 'works', but 8 and 9 get incorrectly converted.
Use
To specify the base explicitly.