用 Erlang 从列表中分割几个头的最佳方法？
所以，与 Erlang 一起工作真的很愉快，但是我偶尔会遇到一个问题，我想知道是否有更好的方法来解决。我经常发现自己需要从列表中拆分多个项目。将列表拆分为 Head 和 Tail 的语法非常简单，但是当有多个项目时该怎么办呢？
1> List = [1,2,3,4,5].
[1,2,3,4,5]
2> [Head | Tail] = List.
[1,2,3,4,5]
3> Head.
1
4> Tail.
[2,3,4,5]
除了内联分割两次之外，是否有更好的方法来获取列表的前两个元素？
1> List = [1,2,3,4,5].
[1,2,3,4,5]
2> [Head1 | [Head2 | Tail]] = List.
[1,2,3,4,5]
3> Head1.
1
4> Head2.
2
5> Tail.
[3,4,5]
我知道这也可以通过编写从列表中递归分割后续头的函数来简化，但我想知道是否有更简单的内联方法来做到这一点（或者事实上，递归后续分割函数是最佳实践完成此任务的方法）？谢谢！
So, Erlang is a real joy to work with, but there's one problem I run into occasionally, that I'm wondering if there is a nicer way to solve. Often, I find myself needing to split several items from a list. The syntax for splitting a list into a Head and Tail is straight forward enough, but what about when there are multiple items.
1> List = [1,2,3,4,5].
[1,2,3,4,5]
2> [Head | Tail] = List.
[1,2,3,4,5]
3> Head.
1
4> Tail.
[2,3,4,5]
Is there a nicer way to get, say, the first two elements of a list other than splitting twice inline?
1> List = [1,2,3,4,5].
[1,2,3,4,5]
2> [Head1 | [Head2 | Tail]] = List.
[1,2,3,4,5]
3> Head1.
1
4> Head2.
2
5> Tail.
[3,4,5]
I know that this can also be simplified by writing functions that recursively split subsequent heads from a list, but I'm wondering if there is a simpler inline way to do it (or if in fact, the recursive subsequent split functions are the best practices way to accomplish this task)? Thanks!
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