使用clone()：分段错误

发布于 2024-09-10 18:22:53 字数 756 浏览 5 评论 0原文

我想使用克隆来记录程序的当前状态。它有很多循环，我想跟踪该过程，而不是在每个循环迭代中打印状态。

这就是我创建这个概念验证的原因：

#include <iostream>
#include <cstdlib>

unsigned int i;

int log(void*) {
  std::cout << "LOGGING START" << std::endl;
  while(true) {
    sleep(1);
    std::cout << i << std::endl;
  }
}

int main()  {
  void **child_stack = (void**)malloc(16384);
  i = 0;

  std::clog << "calling clone" << std::endl;
  clone(log, child_stack, CLONE_VM | CLONE_FILES, NULL);
  std::clog << "done" << std::endl;

  while(true) {
    ++i;
  }

  return 0;
}

当我在没有 gdb 的情况下运行它时，它会因 clone() 处的分段错误而崩溃，但如果我使用 gdb，它就可以正常工作。为什么？

你认为这是一个好的做法还是我迟早会遇到麻烦？有没有更好的方法来实现这一目标？

干杯，

曼努埃尔

原文

I want to use clone to log the current status of my program.
It has a lot of loops and I want to keep track of the process without printing the status in each loop iteration.

That's why I created this proof-of-concept:

#include <iostream>
#include <cstdlib>

unsigned int i;

int log(void*) {
  std::cout << "LOGGING START" << std::endl;
  while(true) {
    sleep(1);
    std::cout << i << std::endl;
  }
}

int main()  {
  void **child_stack = (void**)malloc(16384);
  i = 0;

  std::clog << "calling clone" << std::endl;
  clone(log, child_stack, CLONE_VM | CLONE_FILES, NULL);
  std::clog << "done" << std::endl;

  while(true) {
    ++i;
  }

  return 0;
}

When I run it without gdb it crashes with a segmentation fault at clone() but it works fine if I use gdb. Why?

Do you think this is a good practice or will I run into troubles sooner or later?
And is there a better method to achieve this?

Cheers,

Manuel

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