Django文件上传
我创建了一个应用程序，它将在特定位置上传文件。模型保存后如何读取上传的文件？当我单击 change_field_page 上的文件链接时，它给出找不到页面。我为此使用 Django 1.2 和 django-admin 。
这是我的 models.py：
class UploadClass(models.Model):
id=models.AutoField(primary_key=True)
template_name=models.ForeignKey(sas,verbose_name=ugettext_lazy('Template Name'))
sample=models.FileField(upload_to='%Y/%B/',verbose_name=ugettext_lazy('Sample'))
status=models.IntegerField(ugettext_lazy('Status'),choices=statusChoices,default=0)
created_on=models.DateTimeField(ugettext_lazy('Created on'),auto_now_add=True)
def __unicode__(self):
return (self.template_name.name)
我没有在 forms.py 中执行任何操作。保存对象后如何打开文件？
一种方法是为“url”创建一个视图并返回文件。还有其他人吗？
I have created a app which will upload the file at a particular location. How can I read the file uploaded after the model is saved? When I click on the file link on change_field_page it gives page not found. I'm using Django 1.2 and django-admin for this.
Here's my models.py:
class UploadClass(models.Model):
id=models.AutoField(primary_key=True)
template_name=models.ForeignKey(sas,verbose_name=ugettext_lazy('Template Name'))
sample=models.FileField(upload_to='%Y/%B/',verbose_name=ugettext_lazy('Sample'))
status=models.IntegerField(ugettext_lazy('Status'),choices=statusChoices,default=0)
created_on=models.DateTimeField(ugettext_lazy('Created on'),auto_now_add=True)
def __unicode__(self):
return (self.template_name.name)
I'm not doing anything informs.py. How can I open the file after saving the object?
One way to do this is to create a view for the 'url' and return the file. Are there any others?
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如果文件未从管理员正确链接，请检查您的
MEDIA_ROOT和MEDIA_URL是否最终指向同一位置。另外，您能否举例说明%Y/%B/如何作为文件夹名称？他们可能不像你想象的那样。In terms of the file not being linked correctly from the admin, check your
MEDIA_ROOTand yourMEDIA_URLpoint to, ultimately, the same place. Also, can you give examples of how the%Y/%B/is working out as folder names, please? They may not be as you expect.