XmlSerializer 和可为 null 的属性

发布于 2024-09-10 02:32:07 字数 656 浏览 3 评论 0原文

我有一堂课有很多 Nullable我希望将其序列化为 XML 作为属性。这显然是禁忌,因为它们被认为是“复杂类型”。因此,我实现了 *Specified 模式,其中创建了一个附加 *Value 和 *Specified 属性,如下所示:

[XmlIgnore]
public int? Age
{
    get { return this.age; }
    set { this.age = value; }
}

[XmlAttribute("Age")]
public int AgeValue
{
    get { return this.age.Value; }
    set { this.age = value; }
}

[XmlIgnore]
public bool AgeValueSpecified
{
    get { return this.age.HasValue; }
}

效果很好 - 如果“Age”属性有值,它会被序列化为属性。如果它没有值,则不会序列化。

问题是,正如我提到的,我的类中有很多 Nullable,而这种模式只会让事情变得混乱且难以管理。

我希望有一种方法可以使 Nullable 对 XmlSerializer 更加友好。或者,如果做不到这一点,有一种方法可以创建一个可空替换。

有谁知道我该如何做到这一点?

谢谢。

I have a class with numerous Nullable<T> properties which I want to be serializable to XML as attributes. This is apparently a no-no as they are considered 'complex types'. So, instead I implement the *Specified pattern, where I create an addition *Value and *Specified property as follows:

[XmlIgnore]
public int? Age
{
    get { return this.age; }
    set { this.age = value; }
}

[XmlAttribute("Age")]
public int AgeValue
{
    get { return this.age.Value; }
    set { this.age = value; }
}

[XmlIgnore]
public bool AgeValueSpecified
{
    get { return this.age.HasValue; }
}

Which works fine - if the 'Age' property has a value, it is serialized as an attribute. If it doesn't have a value, it isn't serialized.

The problem is that, as I mentioned, a have a lot of Nullable-s in my class and this pattern is just making things messy and unmanageable.

I'm hoping there is a way to make Nullable more XmlSerializer friendly. Or, failing that, a way to create a Nullable replacement which is.

Does anyone have any ideas how I could do this?

Thanks.

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评论(2

却一份温柔 2024-09-17 02:32:07

我正在处理的一些代码也遇到了类似的问题,我决定只对我正在序列化和反序列化的属性使用字符串。我最终得到了这样的结果:

[XmlAttribute("Age")]
public string Age
{
    get 
    { 
        if (this.age.HasValue)
            return this.age.Value.ToString(); 
        else
            return null;
    }
    set 
    { 
        if (value != null)
            this.age = int.Parse(value);
        else
            this.age = null;
    }
}

[XmlIgnore]
public int? age;

I had a similar problem with some code I was working on, and I decided just to use a string for the property I was serializing and deserializing. I ended up with something like this:

[XmlAttribute("Age")]
public string Age
{
    get 
    { 
        if (this.age.HasValue)
            return this.age.Value.ToString(); 
        else
            return null;
    }
    set 
    { 
        if (value != null)
            this.age = int.Parse(value);
        else
            this.age = null;
    }
}

[XmlIgnore]
public int? age;
老子叫无熙 2024-09-17 02:32:07

在您的类上实现 IXmlSerialized 接口。然后,您可以处理特殊情况,例如 ReadXMLWriteXML 方法中的可空值。 MSDN 文档页面中有一个很好的示例。

 
class YourClass : IXmlSerializable
{
    public int? Age
    {
        get { return this.age; }
        set { this.age = value; }
    }

    //OTHER CLASS STUFF//

    #region IXmlSerializable members
    public void WriteXml (XmlWriter writer)
    {
        if( Age != null )
        {
            writer.WriteValue( Age )
        }
    }

    public void ReadXml (XmlReader reader)
    {
        Age = reader.ReadValue();
    }

    public XmlSchema GetSchema()
    {
        return(null);
    }
    #endregion
}

Implement the IXmlSerializable interface on your class. You can then handle special cases such as nullables in the ReadXML and WriteXML methods. There's a good example in the MSDN documentation page..

 
class YourClass : IXmlSerializable
{
    public int? Age
    {
        get { return this.age; }
        set { this.age = value; }
    }

    //OTHER CLASS STUFF//

    #region IXmlSerializable members
    public void WriteXml (XmlWriter writer)
    {
        if( Age != null )
        {
            writer.WriteValue( Age )
        }
    }

    public void ReadXml (XmlReader reader)
    {
        Age = reader.ReadValue();
    }

    public XmlSchema GetSchema()
    {
        return(null);
    }
    #endregion
}
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