使用 NSHost 访问 IP 地址

Question

我正在尝试使用 NSHost 获取 IP 地址。通过 NSHost 对象，我可以使用地址方法来访问对象数组，其中之一是 IP 地址。但我担心 IP 地址可能会改变阵列中从一台机器到另一台机器的位置。有没有一种方法可以通用地访问这些信息？

在上一篇文章中曾尝试回答这个问题，但正如您所看到的，它没有达到要求。

IP 地址？ - 可可

这是我的代码：

+(NSString *) ipAddress {
    NSHost * h = [[[NSHost currentHost] addresses] objectAtIndex:1];
    return h ;  
}

Answer 1

我唯一能想到的就是使用类似“http://www.dyndns .org/cgi-bin/check_ip.cgi”其他人可能有更好的方法。

这是一个示例，（即快速拼凑在一起的代码）

NSUInteger  an_Integer;
NSArray * ipItemsArray;
NSString *externalIP;

NSURL *iPURL = [NSURL URLWithString:@"http://www.dyndns.org/cgi-bin/check_ip.cgi"];

if (iPURL) {
    NSError *error = nil;
    NSString *theIpHtml = [NSString stringWithContentsOfURL:iPURL 
                                                  encoding:NSUTF8StringEncoding 
                                                     error:&error];
    if (!error) {
                NSScanner *theScanner;
        NSString *text = nil;

        theScanner = [NSScanner scannerWithString:theIpHtml];

        while ([theScanner isAtEnd] == NO) {

                // find start of tag
            [theScanner scanUpToString:@"<" intoString:NULL] ; 

                // find end of tag
            [theScanner scanUpToString:@">" intoString:&text] ;

                // replace the found tag with a space
                //(you can filter multi-spaces out later if you wish)
            theIpHtml = [theIpHtml stringByReplacingOccurrencesOfString:
                    [ NSString stringWithFormat:@"%@>", text]
                                                   withString:@" "] ;
            ipItemsArray =[theIpHtml  componentsSeparatedByString:@" "];
            an_Integer=[ipItemsArray indexOfObject:@"Address:"];

                externalIP =[ipItemsArray objectAtIndex:  ++an_Integer];



        } 


            NSLog(@"%@",externalIP);
    } else {
        NSLog(@"Oops... g %d, %@", 
              [error code], 
              [error localizedDescription]);
    }
}




[pool drain];
return 0;}

Answer 2

我在很多机器上使用过这个，没有任何问题。

 -(void) getIPWithNSHost{
    NSArray *addresses = [[NSHost currentHost] addresses];

for (NSString *anAddress in addresses) {
    if (![anAddress hasPrefix:@"127"] && [[anAddress componentsSeparatedByString:@"."] count] == 4) {
         stringAddress = anAddress;
        break;
    } else {
        stringAddress = @"IPv4 address not available" ;
    }
}
        //NSLog (@"getIPWithNSHost: stringAddress = %@ ",stringAddress);    

}

NSString *字符串地址；在其他地方声明

Answer 3

我想更新关于获取外部 IP 的原始答案。

没有太多变化，但我想展示如何使用 NSXMLDocument 和 Xquary

这也提供了如何通过获取节点来解析 HTML 的小说明。我认为这更直接。虽然 NSXMLDocument 最初是用于 XML 的，但它会解析 HTML DOM 树

    NSString *externalIP;

    ///--DYNDNS.ORG  URL

    NSURL *iPURL = [NSURL URLWithString:@"http://www.dyndns.org/cgi-bin/check_ip.cgi"];
    if (iPURL) {

        NSError *err_p = nil;


        //--use NSXMLDocument to get the url:(*Requests NSXMLNode to preserve whitespace characters (such as tabs and carriage returns) in the XML source that are not part of node content*)
    NSXMLDocument * xmlDoc = [[NSXMLDocument alloc] initWithContentsOfURL:iPURL
                                                                  options:(NSXMLNodePreserveWhitespace|
                                                                           NSXMLNodePreserveCDATA)
                                                                    error:&err_p];

    if (xmlDoc == nil) {

        //-- That did not work so lets see if we can change the malformed XML into valid XML during processing of the document.
        xmlDoc = [[NSXMLDocument alloc] initWithContentsOfURL:iPURL
                                                      options:NSXMLDocumentTidyXML
                                                        error:&err_p];

    }


    if (!err_p) {
 NSError * error;
        //-- We will use XQuary to get the text from the child node. Dyndns.org page is very simple. So we just need to get the Body text.

    NSString *xpathQueryTR =  @"//body/text()";
        //-- we get the first node's string value. We use string value to in effect cast to NSString.
        //We the seperate the string into components using a space. and obtain the last object in the returned array.
        //--This gives us the IP string without the "Current IP Address:" string.
    externalIP = [[[[[xmlDoc nodesForXPath:xpathQueryTR error:&error]objectAtIndex:0] stringValue]componentsSeparatedByString:@" "]lastObject];

    if (!error) {

    NSLog(@"%@",externalIP);

    }else {
        NSLog(@"Oops... g %ld, %@",
              (long)[error code],
              [error localizedDescription]);
    }

    }else {
        NSLog(@"Oops... g %ld, %@",
              (long)[err_p code],
              [err_p localizedDescription]);
    }
}

Answer 4

创建了一个实用程序类来查找 IP 地址。简约的方法。您可以通过更多条件或正则表达式检查来增强它。

 NSLog(@"Addresses: %@", [[NSHost currentHost] addresses]);

返回的列表

 "fe80::1610:9fff:fee1:8c2f%en0",
 "192.168.212.61",
 "fe80::2829:3bff:fee6:9133%awdl0",
 "fe80::e54b:8494:bbc8:3989%utun0",
 "fd68:cc16:fad8:ded9:e54b:8494:bbc8:3989",
 "10.11.51.61",
 "::1",
 "127.0.0.1",
 "fe80::1%lo0"

这是 NSHost测试方法

- (void)testHost {
    NSLog(@"Addresses: %@", [[NSHost currentHost] addresses]);

    for (NSString *s in [[NSHost currentHost] addresses]) {
        IPAddress *addr = [[IPAddress alloc] initWithString:s];
        if (![addr isLocalHost] && [addr isIPV4]) {
            // do something
        }
    }
}

IPAddress.h

#import <Foundation/Foundation.h>

@interface IPAddress : NSObject

@property (nonatomic, strong) NSString *IPAddress;

- (id)initWithString:(NSString *)ipaddress;

- (BOOL)isLocalHost;
- (BOOL) isIPV4;
- (BOOL) isIPV6;

@end

IPAddress.m

#import "IPAddress.h"

@implementation IPAddress

- (id)initWithString:(NSString *)ipaddress {
    self = [super init];
    if (self) {
        self.IPAddress = ipaddress;
    }
    return self;
}

- (BOOL)isLocalHost {
    if (self.IPAddress == nil) return NO;
    if ([@"127.0.0.1" compare:self.IPAddress options:NSCaseInsensitiveSearch] == NSOrderedSame) {
        return YES;
    }

    if ([@"localhost" compare:self.IPAddress options:NSCaseInsensitiveSearch] == NSOrderedSame) {
        return YES;
    }

    if ([@"::1" compare:self.IPAddress options:NSCaseInsensitiveSearch] == NSOrderedSame) {
        return YES;
    }

    return NO;
}

- (BOOL) isIPV4 {
    NSArray *ar = [self.IPAddress componentsSeparatedByString:@"."];
    if (ar.count == 4) {
        return YES;
    }
    return NO;
}

- (BOOL) isIPV6 {
    if (![self isIPV4]) {
        if ([self.IPAddress rangeOfString:@":"].location != NSNotFound) {
            return YES;
        }
    }
    return NO;
}

@end

Answer 5

正如您上面提到的问题的答案所说，一台机器可以拥有多种IP地址。如果这就是您想要的，那么您最好使用 NSHost 的 names 方法来获取名称数组，然后您可以过滤后缀（即 *.lan）以获得名称数组您想要使用此名称的主机的名称。就我而言。 .lan 地址以点线四边形形式返回我的网络 IP 地址。

如果你想找到外部IP地址，那么这是一个 很好的答案看看。

Answer 6

我的第一个答案是提供从您的路由器分配给专用网络上的机器的专用 IP 地址。

如果你想查看公网IP，那就是面向互联网的IP。通常由您的服务提供商分配。您可能想看看 Jim Dovey 的答案 --> 这里

我测试了它，效果很好，但请阅读其余的评论和答案，这些评论和答案指出了试图获得公共 IP 时的含糊之处。

Answer 7

您可以在 NSHost 上创建一个类别并执行如下操作：

#import <arpa/inet.h>
#import <ifaddrs.h>
#import <net/if.h>

.h

+ (NSDictionary *) interfaceIP4Addresses;
+ (NSDictionary *) interfaceIP6Addresses;
+ (NSDictionary *) interfaceIPAddresses;

.m

typedef NS_ENUM(NSUInteger, AddressType) {

    AddressTypeBoth     = 0,
    AddressTypeIPv4     = 1,
    AddressTypeIPv6     = 2
};

@implementation SomeClass

#pragma mark - Helper Methods:

+ (NSDictionary *) _interfaceAddressesForFamily:(AddressType)family {

    NSMutableDictionary *interfaceInfo = [NSMutableDictionary dictionary];
    struct ifaddrs *interfaces;

    if ( (0 == getifaddrs(&interfaces)) ) {

        struct ifaddrs *interface;

        for ( interface=interfaces; interface != NULL; interface=interface->ifa_next ) {

            if ( (interface->ifa_flags & IFF_UP) && !(interface->ifa_flags & IFF_LOOPBACK) ) {

                const struct sockaddr_in *addr = (const struct sockaddr_in *)interface->ifa_addr;

                if ( addr && addr->sin_family == PF_INET ) {

                    if ( (family == AddressTypeBoth) || (family == AddressTypeIPv4) ) {
                        char ip4Address[INET_ADDRSTRLEN];
                        inet_ntop( addr->sin_family, &(addr->sin_addr), ip4Address, INET_ADDRSTRLEN );

                        [interfaceInfo setObject:[NSString stringWithUTF8String:interface->ifa_name]
                                          forKey:[NSString stringWithUTF8String:ip4Address]];

                } } else if ( addr && addr->sin_family == PF_INET6 ) {

                    if ( (family == AddressTypeBoth) || (family == AddressTypeIPv6) ) {
                        char ip6Address[INET6_ADDRSTRLEN];
                        inet_ntop( addr->sin_family, &(addr->sin_addr), ip6Address, INET6_ADDRSTRLEN );

                        [interfaceInfo setObject:[NSString stringWithUTF8String:interface->ifa_name]
                                          forKey:[NSString stringWithUTF8String:ip6Address]];
                } }
            }

        } freeifaddrs( interfaces );

    } return [NSDictionary dictionaryWithDictionary:interfaceInfo];
}

#pragma mark - Class Methods:

+ (NSDictionary *) interfaceIP4Addresses { return [self _interfaceAddressesForFamily:AddressTypeIPv4]; }
+ (NSDictionary *) interfaceIP6Addresses { return [self _interfaceAddressesForFamily:AddressTypeIPv6]; }
+ (NSDictionary *) interfaceIPAddresses  { return [self _interfaceAddressesForFamily:AddressTypeBoth]; }

@end

这工作得非常快而且效果很好。如果您需要其他信息或进行监控，请使用系统配置框架。