从对 Last.FM API 的请求返回的文件中出现错误

发布于 2024-09-09 23:41:37 字数 1389 浏览 3 评论 0原文

我将 Last.fm API 与 jquery 结合使用，如下所示：

$.getJSON('http://ws.audioscrobbler.com/2.0/?JSONCallback=?', {
    method: "user.getweeklytrackchart",
    user: "rj", 
    api_key: "fb04ae401284be24afba0fbc2f4b0efb"
}, function(data) {
    // console.debug (data)
});

我在 Firebug 中收到以下错误：

missing ; before statement
[Break on this error] <lfm status="ok">\n

单击该错误会将我带到从请求返回的文件。错误发生在第 2 行（实际上还有更多的跟踪对象，但我只包含一个长度）：

<?xml version="1.0" encoding="utf-8"?>
<lfm status="ok">
    <weeklytrackchart user="RJ" from="1278244800" to="1278849600">
        <track rank="1">
            <artist mbid="309c62ba-7a22-4277-9f67-4a162526d18a">Beck</artist>
            <name>Mixed Bizzness</name>
            <mbid></mbid>
            <playcount>2</playcount>
            <image size="small">http://userserve-ak.last.fm/serve/34/442288.jpg</image>
            <image size="medium">http://userserve-ak.last.fm/serve/64/442288.jpg</image>
            <image size="large">http://userserve-ak.last.fm/serve/126/442288.jpg</image>
            <url>www.last.fm/music/Beck/_/Mixed+Bizzness</url>
        </track>
    </weeklytrackchart>
</lfm>

所以错误出现在返回的文件中，我该如何处理它？感谢您的阅读。

原文

I'm using the Last.fm API with jquery as follows:

$.getJSON('http://ws.audioscrobbler.com/2.0/?JSONCallback=?', {
    method: "user.getweeklytrackchart",
    user: "rj", 
    api_key: "fb04ae401284be24afba0fbc2f4b0efb"
}, function(data) {
    // console.debug (data)
});

I'm getting the following error in Firebug:

missing ; before statement
[Break on this error] <lfm status="ok">\n

Clicking on the error takes me to the file that gets returned from the request. The error is occurring in line 2 (there are actually many more of the track objects but I've only included one for length):

<?xml version="1.0" encoding="utf-8"?>
<lfm status="ok">
    <weeklytrackchart user="RJ" from="1278244800" to="1278849600">
        <track rank="1">
            <artist mbid="309c62ba-7a22-4277-9f67-4a162526d18a">Beck</artist>
            <name>Mixed Bizzness</name>
            <mbid></mbid>
            <playcount>2</playcount>
            <image size="small">http://userserve-ak.last.fm/serve/34/442288.jpg</image>
            <image size="medium">http://userserve-ak.last.fm/serve/64/442288.jpg</image>
            <image size="large">http://userserve-ak.last.fm/serve/126/442288.jpg</image>
            <url>www.last.fm/music/Beck/_/Mixed+Bizzness</url>
        </track>
    </weeklytrackchart>
</lfm>

So the error is in the returned file, how do I deal with it? Thanks for reading.

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假装爱人 2024-09-16 23:41:37

这里有一些问题。

首先，我认为请求 URL 末尾的 JSONCallback=? 参数应该是 callback=?。尽管令人困惑的是 jQuery 文档在示例代码中显示了您的方式，但在主体中却没有显示text...

另一件事是您正在使用 getJSON 方法，而 Last.fm API 返回 XML，因此 jQuery 尝试将返回的 XML 解析为 JSON，这显然可以'不做。

因此，您需要指定您希望返回 JSON 作为响应，这似乎可行：

$.getJSON('http://ws.audioscrobbler.com/2.0/?callback=?', {
    method: "user.getweeklytrackchart",
    user: "rj",
    api_key: "fb04ae401284be24afba0fbc2f4b0efb",
    format: "json"
}, function(data) {
    console.log(data);
});

您将能够在 Firebug 控制台中看到返回的 JSON 对象，并检查它以了解您想要使用哪些数据。希望这有帮助！

There are a couple of things wrong here.

First, I think the JSONCallback=? parameter you have on the end of the request url should just be callback=?. Although confusingly the jQuery docs show your way in the example code, but not in the main body text...

The other thing is that you are using the getJSON method, while the Last.fm API is returning XML, so jQuery is attempting to parse that returned XML as JSON, which it obviously can't do.

So you need to specify that you'd like JSON back as a response—this seems to work:

$.getJSON('http://ws.audioscrobbler.com/2.0/?callback=?', {
    method: "user.getweeklytrackchart",
    user: "rj",
    api_key: "fb04ae401284be24afba0fbc2f4b0efb",
    format: "json"
}, function(data) {
    console.log(data);
});

You will be able to see the returned JSON object in the Firebug console and examine it to see which data you want to use. Hope this helps!

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