linq to xml - 基于数组或列表显示结果

发布于 2024-09-09 11:06:13 字数 589 浏览 1 评论 0原文

我有一个 xml 文件，我想在其中进行查询以显示其中包含某些 Id 的所有文章。这是我尝试过的，但不知何故我无法让它工作。我环顾四周，发现的只是使用 linq to sql 的示例。

任何帮助将不胜感激...

干杯， Terry

id 在 xml 中像这样存储

<relatedcontent articleID="1, 2, 3, 4" />

这是我的 linq

 var mylinks = (from item in relatedLinks.Descendants("link") 
    where item.Attribute("linkID").Value.Contains("1, 2")
        select new
          {
            testlink = item.Value
          });

    foreach (var newarticles in mylinks)
       {
         Response.Write(newarticles .testlink);
       }

原文

I have a xml file on which I want to make a query to display all articles with certain Id's in it.This is what I tried but somehow I can't get it to work.
I looked around and all I could find were examples using linq to sql.

Any help would be appreciated...

Cheers,
Terry

The id's are stored like this in the xml

<relatedcontent articleID="1, 2, 3, 4" />

Here's my linq

 var mylinks = (from item in relatedLinks.Descendants("link") 
    where item.Attribute("linkID").Value.Contains("1, 2")
        select new
          {
            testlink = item.Value
          });

    foreach (var newarticles in mylinks)
       {
         Response.Write(newarticles .testlink);
       }

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

梦幻的味道 2024-09-16 11:06:14

您现在要做的是查找 Id 包含字符串“1, 2”的文章，就像 Id 为“5,8,1,2,9”一样。

你想要的可能恰恰相反；查找Id为“1, 2”的文章，即Id为“1”和“2”的文章：

var ids = new HashSet<string>();
ids.Add("1");
ids.Add("2");

var mylinks =
  from item in relatedLinks.Descendants("link") 
  where ids.Contains(item.Attribute("linkID").Value)
  select new { testlink = item.Value };

What you are doing now is to look for articles where the Id contains the string "1, 2", like if the Id was "5, 8, 1, 2, 9".

What you want is probably the opposite; to find the articles where "1, 2" contains the Id, i.e. the articles with Id "1" and "2":

var ids = new HashSet<string>();
ids.Add("1");
ids.Add("2");

var mylinks =
  from item in relatedLinks.Descendants("link") 
  where ids.Contains(item.Attribute("linkID").Value)
  select new { testlink = item.Value };

回复收藏 0 原文

~没有更多了~