在 XAML 中根据菱形的倾斜因子创建倾斜角度Y
我不确定这是否可能，但基本上我有两个度数可以改变图像的宽度/大小和倾斜。在变换矩阵 (
M11:cos(x) M12:sin(y)*sin(x) M11:0 M21:0 M22:cos(y) M23:0 M31:0 M32:0 M33:1
因此，如果我有 X = 30° 和 Y=40° code>，我的矩阵是：
M11:0.866 M12:0.321 M11:0 M21:0 M22:0.766 M23:0 M31:0 M32:0 M33:1
所以 
变为 
我想使用的是 ScaleX 和 中使用上面的 M11 和 M22 值， 就像
但我无法从 M12 值 0.321AngleY 部分>。我知道，通过手动处理，AngleY="20.3" 的值似乎非常准确。但我无法弄清楚这背后的数学原理。
有谁知道吗？
I'm not sure if this is possible, but basically I have two degrees that will change the width/size and skew of an image. In a tranformation matrix (<Matrix3DProjection/>), it works like this:
M11:cos(x) M12:sin(y)*sin(x) M11:0 M21:0 M22:cos(y) M23:0 M31:0 M32:0 M33:1
So if I have X = 30° and Y=40°, my matrix is:
M11:0.866 M12:0.321 M11:0 M21:0 M22:0.766 M23:0 M31:0 M32:0 M33:1
So becomes 
What I'd like to use instead is a <TransformGroup/> but can't quite figure out the <SkewTransform AngleY="???"/> portion. The <ScaleTransform/> seems easy enough by using M11 and M22 values above in ScaleX and ScaleY like <ScaleTransform ScaleX=".866" ScaleY=".766"/>.
But I can't figure out the AngleY portion of <SkewTransform/> from an M12 value of 0.321. I know that from doinking around with this manually, a value of AngleY="20.3" seems very accurate. But I can't figure out the math behind this.
Does anyone know?
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您可以在 SkewTransform 类上使用 Reflector 来找出数学原理。它调用 Matrix.Skew，它使用矩阵：
由于您想要
tan(skewY) * 0.766 = 0.321，因此您会得到skewY = atan(0.321 / 0.766) = 22.7366108 度。或者，回到原来的数字，skewY = atan(sin(y) * sin(x) / cos(y)) = atan(tan(y) * sin(x))，其中得出 atan(tan(40 度) * sin(30 度)) = 22.7604763 度。You can use Reflector on the SkewTransform class to find out the math. It calls Matrix.Skew, which uses the matrix:
Since you want
tan(skewY) * 0.766 = 0.321, you getskewY = atan(0.321 / 0.766) = 22.7366108 degrees. Or, going back to your original numbers,skewY = atan(sin(y) * sin(x) / cos(y)) = atan(tan(y) * sin(x)), which yieldsatan(tan(40 degrees) * sin(30 degrees)) = 22.7604763 degrees.尝试从字里行间解读一下您是否想避免使用
Projection属性并改用RenderTransform？如果是这样，而不是尝试弄清楚如何使用 ScaleTransform 和 SkewTransform ，只需使用 RenderTransform 中的 MatrixTransform 即可。
或者
Trying to read between the lines a little you want to avoid using the
Projectionproperty and use to theRenderTransforminstead?If so rather than trying to work out how to use
ScaleTransformandSkewTransformjust use theMatrixTransformin theRenderTransform.OR