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c 数据类型大小

发布于 2024-09-09 04:46:15 字数 26 浏览 1 评论 0原文

我如何知道计算机中所有数据类型的大小？

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趴在窗边数星星i 2024-09-16 04:46:16

下面的程序应该可以解决基本类型的问题：

#include <stdio.h>
int main()
{
    printf("sizeof(char) = %d\n", sizeof(char));
    printf("sizeof(short) = %d\n", sizeof(short));
    printf("sizeof(int) = %d\n", sizeof(int));
    printf("sizeof(long) = %d\n", sizeof(long));
    printf("sizeof(long long) = %d\n", sizeof(long long));
    printf("sizeof(float) = %d\n", sizeof(float));
    printf("sizeof(double) = %d\n", sizeof(double));
    printf("sizeof(long double) = %d\n", sizeof(long double));
    return 0;
}

这会打印该类型使用的“字节”数，根据定义 sizeof(char) == 1。 1 的含义（即有多少位）是特定于实现的，并且可能取决于底层硬件。例如，有些机器有 7 位字节，有些机器有 10 或 12 位字节。

The following program should do the trick for the primitive types:

#include <stdio.h>
int main()
{
    printf("sizeof(char) = %d\n", sizeof(char));
    printf("sizeof(short) = %d\n", sizeof(short));
    printf("sizeof(int) = %d\n", sizeof(int));
    printf("sizeof(long) = %d\n", sizeof(long));
    printf("sizeof(long long) = %d\n", sizeof(long long));
    printf("sizeof(float) = %d\n", sizeof(float));
    printf("sizeof(double) = %d\n", sizeof(double));
    printf("sizeof(long double) = %d\n", sizeof(long double));
    return 0;
}

This prints the number of "bytes" the type uses, with sizeof(char) == 1 by definition. Just what 1 means (that is how many bits that is) is implementation specific and likely depend on the underlying hardware. Some machines have 7 bit bytes for instance, some have 10 or 12 bit bytes.

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