如何捕获 PHP 中对象的任何方法调用？

发布于 2024-09-09 00:42:46 字数 594 浏览 6 评论 0原文

我试图弄清楚如何捕获 PHP 中对象调用的任何方法。我知道魔术函数__call，但它仅针对被调用对象上不存在的方法触发。

例如，我有这样的东西：

class Foo
{
  public function bar()
  {
    echo 'foobar';
  }

  public function override($method_name,$method_args)
  {
    echo 'Calling method ',$method_name,'<br />';
    $this->$method_name($method_args); //dirty, but working
  }
}

当我这样做时：

$foo = new Foo();
$foo->bar();

我想要这个输出：

Calling method bar
foobar

而不是这个：

foobar

有什么方法可以做到这一点吗？请帮忙:)

原文

I am trying to figure out how to catch any method called on an object in PHP. I know about the magic function __call, but it is triggered only for methods that do not exist on the called object.

For example i have something like this:

class Foo
{
  public function bar()
  {
    echo 'foobar';
  }

  public function override($method_name,$method_args)
  {
    echo 'Calling method ',$method_name,'<br />';
    $this->$method_name($method_args); //dirty, but working
  }
}

And when i do this:

$foo = new Foo();
$foo->bar();

I want this output:

Calling method bar
foobar

instead of this one:

foobar

Is there any way how to do this? Help please :)

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隔岸观火 2024-09-16 00:42:46

采用原始的 Foo 实现，您可以将 decorator 包裹在它周围，如下所示：

class Foo 
{
    public function bar() {
        echo 'foobar';
    }
}

class Decorator 
{
    protected $foo;

    public function __construct(Foo $foo) {
       $this->foo = $foo;
    }

    public function __call($method_name, $args) {
       echo 'Calling method ',$method_name,'<br />';
       return call_user_func_array(array($this->foo, $method_name), $args);
    }
}

$foo = new Decorator(new Foo());
$foo->bar();

Taking your original Foo implementation you could wrap a decorator around it like this:

class Foo 
{
    public function bar() {
        echo 'foobar';
    }
}

class Decorator 
{
    protected $foo;

    public function __construct(Foo $foo) {
       $this->foo = $foo;
    }

    public function __call($method_name, $args) {
       echo 'Calling method ',$method_name,'<br />';
       return call_user_func_array(array($this->foo, $method_name), $args);
    }
}

$foo = new Decorator(new Foo());
$foo->bar();

回复收藏 0 原文

星 2024-09-16 00:42:46

您可以将对象包装在对象周围，拦截任何调用，然后将它们转发到原始对象并返回结果。

只需将对象作为变量存储在包装类中，并在包装类中使用重载方法来调用/设置/获取/检查该对象。

$object = new AnyObject;
$object = new Wrapper($object);

$object->anyMethod();
$object->anyVar = 'test';
echo $object->anyVar;
echo $object['array form'];

在 foreach 中循环包装类可能更困难。没试过。

You can wrap an object around the object, intercepting any calls then forwarding them on the original object and returning the result.

Just store the object as a variable in your wrapper class and use overloading methods in your wrapper class to call/set/get/check on the object.

$object = new AnyObject;
$object = new Wrapper($object);

$object->anyMethod();
$object->anyVar = 'test';
echo $object->anyVar;
echo $object['array form'];

Looping the wrapper class in foreach is probably harder. Havent tried that.

回复收藏 0 原文

半世蒼涼 2024-09-16 00:42:46

如果将函数设置为 private ，则 call 将捕获任何从外部对其进行的调用将被捕获在 __call 中，但您可以从内部调用它

class Foo
{
   private function bar()
   {
      echo 'foobar';
   }

   public function __call($method_name,$method_args)
   {
      echo 'Calling method ',$method_name,'<br />';
      $this->$method_name(); //dirty, but working
   }
}

If you set the function to private , call will trap any call to it from the outside will be trapped in __call, but you can call it from the inside

class Foo
{
   private function bar()
   {
      echo 'foobar';
   }

   public function __call($method_name,$method_args)
   {
      echo 'Calling method ',$method_name,'<br />';
      $this->$method_name(); //dirty, but working
   }
}

回复收藏 0 原文

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