构建 MVC ActionLink 的正确方法

发布于 2024-09-08 23:16:11 字数 271 浏览 1 评论 0原文

我有一个像这样的 MVC ActionLink （效果很好）

<%: Html.ActionLink(user.UserName, "Details", "Users", New With{.id = user.ID, .slug = Replace(user.UserName," ","-")}, nothing)%>

但是由于不“建议”在视图中进行字符串操作，我想知道如何构建一个自定义 Html ActionLink 来为我进行字符串替换？

原文

I've got an MVC ActionLink like so (which works just fine)

<%: Html.ActionLink(user.UserName, "Details", "Users", New With{.id = user.ID, .slug = Replace(user.UserName," ","-")}, nothing)%>

But since it's not "recommended" to do string manipulation in the View, I'm wondering how I could build a custom Html ActionLink to do the string replacement for me?

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宛菡 2024-09-15 23:16:11

自定义 ActionLink 似乎也是错误的地方，最好通过自定义视图模型将 Slug 从控制器传递到视图。 Slug 可以是视图模型上的属性以及 setter 中调用的字符串逻辑。

例如，将 UserViewModel 类添加到“ViewModels”文件夹中。

public class UserViewModel
{
  public User User { get; private set; }
  public string Slug { get; private set; }

  public UserViewModel(User user)
  {
      Slug = Replace(user.UserName," ","-");
  }
}

然后在控制器中，将其传递给视图：

return View(new UserViewModel(user))

有关 ViewModel 用法的更多信息：

MVC 视图模型模式

The custom ActionLink seems to be the wrong place to do it as well, better to pass the Slug via a custom View Model to the view from the controller. The Slug could be a property on the View Model and the string logic invoked in the setter.

For example add a UserViewModel class to a "ViewModels" folder.

public class UserViewModel
{
  public User User { get; private set; }
  public string Slug { get; private set; }

  public UserViewModel(User user)
  {
      Slug = Replace(user.UserName," ","-");
  }
}

Then in the controller, pass it to the view as: