SQL `order`.id 未知列中的变量范围

发布于 2024-09-08 22:30:42 字数 1244 浏览 2 评论 0原文

在以下查询中，INNER JOIN 中的 order.id 引用引发了错误 Unknown column 'order.id' in 'on Clause'。 id 列确实存在。

有什么想法为什么不能通过子查询访问它吗？

SELECT
    SUM(price+shipping_price) AS total_sales,
    COUNT(id) AS total_orders,
    AVG(price+shipping_price) AS order_total_average,
    (SELECT
            SUM(quantity)
        FROM `order_product`
        WHERE `order`.id = order_product.order_id
    ) as total_units,
    SUM(price+shipping_price)/7 as daily_average,
    (SELECT
            SUM(order_product.price * order_return_product.quantity)
        FROM order_return_product
        INNER JOIN order_product ON (
            order_product.order_id = `order`.id AND
            order_product.product_id = order_return_product.product_id AND
            order_product.vehicle_id = order_return_product.vehicle_id
        )
        WHERE return_id IN (
            SELECT
                id
            FROM order_return
            WHERE status_id != 3 AND
            order_return.order_id = `order`.id
        )
    ) as total_returns
FROM `order`
WHERE created >= 1278388801 AND
created <= 1279079999 AND
fraud = 0 AND
type_id = 4

当我注释掉 INNER JOIN 中的 order.id 时，我没有收到任何错误

原文

In the following query, the error Unknown column 'order.id' in 'on clause' is being thrown by my order.id reference in the INNER JOIN. The id column does indeed exist.

Any ideas why it's not accessible via the sub query?

SELECT
    SUM(price+shipping_price) AS total_sales,
    COUNT(id) AS total_orders,
    AVG(price+shipping_price) AS order_total_average,
    (SELECT
            SUM(quantity)
        FROM `order_product`
        WHERE `order`.id = order_product.order_id
    ) as total_units,
    SUM(price+shipping_price)/7 as daily_average,
    (SELECT
            SUM(order_product.price * order_return_product.quantity)
        FROM order_return_product
        INNER JOIN order_product ON (
            order_product.order_id = `order`.id AND
            order_product.product_id = order_return_product.product_id AND
            order_product.vehicle_id = order_return_product.vehicle_id
        )
        WHERE return_id IN (
            SELECT
                id
            FROM order_return
            WHERE status_id != 3 AND
            order_return.order_id = `order`.id
        )
    ) as total_returns
FROM `order`
WHERE created >= 1278388801 AND
created <= 1279079999 AND
fraud = 0 AND
type_id = 4

I get no errors when I comment out order.id within the INNER JOIN

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寻梦旅人 2024-09-15 22:30:42

order.id 超出此查询的范围 - 您仅处理子查询中的 order_return_product 和 order_product 表。

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属性 2024-09-15 22:30:42

试试这个：

SELECT
    SUM(order_product.price * order_return_product.quantity)
FROM order_return_product
INNER JOIN order_product ON (
    order_product.product_id = order_return_product.product_id AND
    order_product.vehicle_id = order_return_product.vehicle_id
)
WHERE return_id IN (
    SELECT
        id
    FROM order_return
    WHERE status_id != 3 AND
    order_return.order_id = `order`.id
) 
AND order_product.order_id = `order`.id

...对于total_returns子查询

try this:

SELECT
    SUM(order_product.price * order_return_product.quantity)
FROM order_return_product
INNER JOIN order_product ON (
    order_product.product_id = order_return_product.product_id AND
    order_product.vehicle_id = order_return_product.vehicle_id
)
WHERE return_id IN (
    SELECT
        id
    FROM order_return
    WHERE status_id != 3 AND
    order_return.order_id = `order`.id
) 
AND order_product.order_id = `order`.id

... for the total_returns subquery

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