带有列表的结构<..> 2 暗淡。动态数组删除时出现段错误

发布于 2024-09-08 19:23:36 字数 423 浏览 1 评论 0 原文

对于一个小项目，我想使用一个带有 stl 容器的结构。然后这个东西被打包成一个动态的 2 点。数组，但是当我尝试删除它时，它出现段错误。

这是代码：

struct cell{
    list<pair<double, double> > alist;

};
int main()
{
   struct cell ** myAr = new cell*[5];
   for(int i = 0; i < 5; ++i)
      myAr[i] = new cell[5];

   for(int j = 0; j < 5; ++j)
      delete myAr[j];
   delete myAr; 

   return 0;
}

任何人都可以帮我解决这个问题吗？提前致谢。弗洛。

原文

for a little project i wanted to use a struct with an stl container in it.
This thingy is then packet into a dynamic 2 dim. array, but when i try to delete it,
it segfaults.

Here is the code:

struct cell{
    list<pair<double, double> > alist;

};
int main()
{
   struct cell ** myAr = new cell*[5];
   for(int i = 0; i < 5; ++i)
      myAr[i] = new cell[5];

   for(int j = 0; j < 5; ++j)
      delete myAr[j];
   delete myAr; 

   return 0;
}

Can anyone help me with this?
Thanks in advance.
Flo.

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眼中杀气 2024-09-15 19:23:36

使用 delete[] 来分配通过 new[] 分配的内存：

for(int j = 0; j < 5; ++j)
    delete[] myAr[j];
delete[] myAr;

Use delete[] for memory allocated with new[]:

for(int j = 0; j < 5; ++j)
    delete[] myAr[j];
delete[] myAr;

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野侃 2024-09-15 19:23:36

您使用 new[] 进行分配，因此需要使用 delete[] 进行释放：

for(int j = 0; j < 5; ++j)
      delete [] myAr[j];
   delete [] myAr;

You allocated with new[] so you need to free with delete[]:

for(int j = 0; j < 5; ++j)
      delete [] myAr[j];
   delete [] myAr;

回复收藏 0 原文

旧时浪漫 2024-09-15 19:23:36

int main()
{
   struct cell ** myAr = new cell*[5];
   for(int i = 0; i < 5; ++i)
      myAr[i] = new cell[5];

   for(int j = 0; j < 5; ++j)
      {
       delete[] myAr[j];
       myAr[j] = 0;
       }
   delete[] myAr; 
   myAr = 0;

   return 0;
}

int main()
{
   struct cell ** myAr = new cell*[5];
   for(int i = 0; i < 5; ++i)
      myAr[i] = new cell[5];

   for(int j = 0; j < 5; ++j)
      {
       delete[] myAr[j];
       myAr[j] = 0;
       }
   delete[] myAr; 
   myAr = 0;

   return 0;
}

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