C++:从向量中删除项目很困难
我正在尝试从向量中删除一个元素。
vector<Foo> vecFoo;
Foo f1;
Foo f2;
Foo f3;
vecFoo.push_back(f1);
vecFoo.push_back(f2);
vecFoo.push_back(f3);
Foo* pF1 = &f1;
vecFoo.erase(std::remove(vecFoo.begin(), vecFoo.end(), *pF1), vecFoo.end());
最后一行产生大量 C2784 错误。我做错了什么?
(是的,这个例子有点做作,但本质是我有一个指向向量中元素的指针,并且我想删除该元素。)
I'm trying to remove an element from a vector.
vector<Foo> vecFoo;
Foo f1;
Foo f2;
Foo f3;
vecFoo.push_back(f1);
vecFoo.push_back(f2);
vecFoo.push_back(f3);
Foo* pF1 = &f1;
vecFoo.erase(std::remove(vecFoo.begin(), vecFoo.end(), *pF1), vecFoo.end());
That last line produces a huge amount of C2784 errors. What am I doing wrong?
(Yes, this example is bit contrived, but the essence is that I've got a pointer to an element in the vector, and I want to remove that element.)
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您是否缺少比较运算符?
Are you missing the comparison operator?
您没有指向该元素的指针,因为 push_back 会进行复制。您可以使用 Foo* pF1 = &vecFoo[0]; 来修复这个问题。
假设这只是一个拼写错误,您可以非常简单地获得元素的迭代器,因为向量迭代器是随机访问的。
You don't have a pointer to the element, because push_back makes a copy. You could fix that with
Foo* pF1 = &vecFoo[0];
Assuming that was just a typo, you can get an iterator to the element very simply, since vector iterators are random access.
您是否重载了
Foo
的operator==
?Foo
是否有一个重要的析构函数、赋值运算符或复制构造函数,但不是全部三个?如果定义其中一个,则必须定义全部。即使您没有重载析构函数、赋值运算符或复制构造函数,
Foo
的成员之一也已将其析构函数、赋值运算符或复制构造函数声明为私有。Have you overloaded
Foo
'soperator==
?Does
Foo
have a non-trivial destructor, assignment operator, or copy constructor, but not all three? If you define one, you must define them all.Even if you haven't overloaded the destructor, assignment operator, or copy constructor, one of you
Foo
's members have declared private its destructor or assignment operator or copy constructor.